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Alinara [238K]
2 years ago
12

Please answer this thank you

Mathematics
1 answer:
exis [7]2 years ago
7 0

Step-by-step explanation:

option 1

option 3

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12, 21, 30 and 39 are the first four terms in a sequence
vivado [14]

Answer:

12, 21, 30, 39, 48, 57, 66, 75, 84.  

Ninth term is 84.

Step-by-step explanation:

The rule for this sequence is "add 9".

So, using this rule, we can do......

12, 21, 30, 39, 48, 57, 66, 75, 84.

<em>Remember to add 9 each time!</em>

Best of luck :3

4 0
3 years ago
5(k+5)+4&lt;21+6k what is the answer
Temka [501]
Solve whats in the parentheses first
5k+25+4<21+6k

5k+29<21+6k

plug in a number in k for both sides
5(1)+29<21+6(1)
5+29<21+6
34<27

5(2)+29<21+6(2)
10+29<21+12
39<33

so 5(k+5)+4 is greater than 21+6k
4 0
3 years ago
Dean used a triple beam balance to find that the mass of a rock was 40 g and he used a graduate cylinder that measures the volum
zhenek [66]

Answer:

Never bwa hahaha JK try d

Step-by-step explanation:

4 0
3 years ago
5x + 9 = 5 + 3x : solve
earnstyle [38]

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              Hi my lil bunny!

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5x - 9 = 5 - 3x

5x - 3x = 5 - 9

2x = -4

X = \frac{-4}{2} = -2

❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙

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Hope this helped you.

Could you maybe give brainliest..?

❀*May*❀

5 0
3 years ago
How many atoms are in the given sample 214.1 g of Vanadium
lord [1]

Answer:

The atomic weight (or atomic mass) of Vanadium is 50.9415 which means that a "mole" of Vanadium atoms (6.02 x 10^23 atoms) will have a mass of 50.9415 grams.  So, 214.1 grams of Vanadium would have

(214.1 / 50.9415) * (6.02 x 10^23) = 2.530 x 10^24 atoms



Step-by-step explanation:


6 0
3 years ago
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