March, April, and May correspond to 3,4, and 5th months. Each month the amount of money he saves increases by $40, so this is a constant rate of change, or constant velocity, which means that this is a linear equation. Let y=the amount of money he has and x=the month number and model it with the line of form y=mx+b, where m=slope, or rate, and b=y-intercept...
y=40x+b, we know that he has $40 on the third month (February) so:
40=40(3)+b
40=120+b
-80=b so the equation is:
y=40x-80 (note that the domain is x=[3, +oo) only for the function to have meaining)
Now you want to know when he has $320...
320=40x-80
400=40x
10=x
So he will have $320 on the 10th month, which is October.
Answer:
A/ (L ⋅ W) =H
Step-by-step explanation:
A = L ⋅ W ⋅ H
A/ (L ⋅ W) =H
Explanation:
For a quadratic equation in standard form with real coefficients:

The quadratic formula giving its solutions is ...

The quantity under the radical is called the discriminant. If we let d represent it, then ...
d = b²-4ac
and there are three possibilities:
- d < 0. The solutions involve the square root of a negative number, so both are complex. They are conjugates of each other.
- d = 0. There is one real solution. It has multiplicity 2.
- d > 0. There are two distinct real roots.
If the coefficients of the quadratic are rational, the roots will be irrational if and only if d is not a perfect square.
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The above formula still applies when coefficients are complex or irrational (or both). In the case of complex coefficients, the description of the number of roots is accurate, but their description as real or complex may not apply.
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<u>Examples</u>:
(x -1)² +1 = 0 = x² -2x +2 . . . . d = (-2)²-4(1)(2) = -4; roots are x = 1 ± i
(x-2)² = 0 = x² -4x +4 . . . . . . d = (-4)² -4(1)(4) = 0; roots are x = 2 (twice)
(x+3)² -4 = x² +6x +5 . . . . . . d = 6² -4(1)(5) = 16; roots are x = -5 and x = -1
75,88,90,96,98,100
minimum = 75
Q1 = 88.....this is where the box begins
Q2 (the median) = (90 + 96) / 2 = 186/2 = 93....this is the line in the box
Q3 = 98....this is where the box ends
maximum = 100
88_93______98
75_______| | |___100
|___|_______|
Step-by-step explanation:
please see it my steps to work this problem