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Zepler [3.9K]
3 years ago
12

Jimmy is a tutor in the science club. He charges $40 per semester to privately

Mathematics
1 answer:
baherus [9]3 years ago
8 0

Answer:

He made less than 4 home visits

Step-by-step explanation:

40 is the fee + 10  per home visit

40 + 10 h

He made less than 80

40 + 10 h< 80

Subtract 40 from each side

40 + 10h-40 < 80-40

10 h< 40

Divide by 10

10h/10 < 40/10

h < 4

He made less than 4 home visits

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An integer is 8 more than 5 times another. If the product of the two integers is 36, then find the integers
Harman [31]

Answer:

see below

Step-by-step explanation:

1st:  x

2nd:  5x + 8

x(5x + 8) = 36

5x² + 8x = 36

5x² + 8x - 36 = 0

(x - 2)(5x + 18) = 0

(x - 2) = 0

x - 2 = 0

x = 2

1st:  x = 2

2nd:  5x + 8 = 5(2) + 8 = 18

(5x + 18) = 0

5x + 18 = 0

5x = -18

x = -3.6

1st:  x = -3.6

2nd:  5x + 8 = 5(-3.6) + 8 = -18 + 8 = -10

7 0
3 years ago
How do i find the volume of a cone
enyata [817]
V=PiR^2H/3

Pi = 3.14 (use pi symbol on calculator)
R is the radius if the cones bottom
H is the height of the cone
3 0
3 years ago
Read 2 more answers
Explain why thirteen
insens350 [35]

Answer:

thirteen hundredths=13/100

one hundred thirty thousandths=130/1000

cancelling by 10 this is =13/100

hence the question

Step-by-step explanation:

7 0
4 years ago
Read 2 more answers
What needs to be corrected in this construction of a line parallel to AB passing through C?
monitta

Answer;

C) The second arc should be centered at C.

Explanation;

Assuming the goal is to construct a line parallel to AB that passes through given point C.

-Draw a line through C and across AB at an angle creating D.

- With the compass width about half of DC, and center D, draw the first arc to cross both lines.

-Using the same compass width , draw the second arc with center C.

-Then set the compass width to the lower arc (the first arc)

- Move the compass to the second arc. Mark off an arc to make point E

-Draw a straight line through C and E

Thus the line CE will be parallel to line AB

3 0
3 years ago
Read 2 more answers
An envelope is 11 inches wide and measures 19 inches along the diagonal.How tall in inches is the envelope
nataly862011 [7]

Answer:

The envelop is 15.49 inches tall

Step-by-step explanation:

To find how tall the envelop is, we will follow the steps below;

We can use Pythagoras theorem formula to find the height of the envelop'

adjacent =width of the envelop= 11 inches   opposite= height (h)  of the evelope = h      and hypotenuse = diagonal of the envelop= 19 inches

Using Pythagoras theorem;

opposite² + adjacent² = hypotenuse²

h² + 11² = 19²

h² + 121 = 361

subtract 121 from both-side of the equation

h² + 121-121 = 361-121

h²  = 240

Take the square root of both-side

√h²  =√ 240

h≈15.49 inches

The envelop is 15.49 inches tall

7 0
4 years ago
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