Total number of ways to make a pair:
The first player can be any one of 7 . For each of those . . .
The opponent can be any one of the remaining 6 .
Total ways to make a pair = 7 x 6 = 42 ways .
BUT ... every pair can be made in two ways ... A vs B or B vs A .
So 42 'ways' make only (42/2) = 21 different pairs.
If every pair plays 2 matches, then (21 x 2) = <em><u>42 total matches</u></em> will be played.
Now, is that an elegant solution or what !
Answer:
I think it might be 14.28.
Step-by-step explanation:
I used a triangle calculator "cossincalc.com"
Answer:
-x+5
Step-by-step explanation:
5-5x+4x
= 5+(-5x)+4x
combine like terms:
5+(-5x)+4x
(-5x+4x)+(5)
= -x+5
The answer is the first option

by using the integration formula
we get,

now put the value of t=\sin\theta in the above equation
we get,

hence proved