Answer:
Distance= 6.6 miles
Bearing= N 62.854°W
Step-by-step explanation:
Let's determine angle b first
Angle b=20° (alternate angles)
Using cosine rule
Let the distance between the liner and the port be x
X² =8.8²+2.4²-2(8.8)(2.4)cos20
X²= 77.44 + 5.76-(39.69)
X²= 43.51
X= √43.51
X= 6.596
X= 6.6 miles
Let's determine the angles within the triangle using sine rule
2.4/sin b = 6.6/sin20
(2.4*sin20)/6.6= sin b
0.1244 = sin b
7.146= b°
Angle c= 180-20-7.146
Angle c= 152.854°
For the bearing
110+7.146= 117.146
180-117.146= 62.854°
Bearing= N 62.854°W
keeping in mind that a line with a slope of "0" is a horizontal line, Check the picture below.
In this question, we have to find the complement and supplement of the given angles .
Complementary angles are those angles whose sum is 90 degree and supplementary angles are those angles whose sum is 180 degree.
So to find the complement and supplement angles, we need to subtract the given angles from pi/2 and pi respectively .
a.
b.
Answer:
this is only one functions, it means all is correct.
-7 * 3 = -21 so the answer is
-3 3/7
