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IgorLugansk [536]
3 years ago
6

For a shape to be symmetrical do both sides have to be the same when divided?

Mathematics
2 answers:
rewona [7]3 years ago
6 0
Yes in order for them to be symmetrical they both have to be Symmetrical or the same
Over [174]3 years ago
5 0

Answer:

Yes, they should be the same when dividing

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You have a shelf that holds 25 1/2 pounds. What is the most number of 1 1/4 pound books that the shelf can hold?​
patriot [66]

Answer:

20 books

Step-by-step explanation:

given that the shelf can hold 25 1/2 lbs (i.e 25.5 lbs), and that each book weighs 1 1/4 ln (i.e 1.25 lbs)

number of books which the shelf can hold

= weight that the shelf can hold ÷ weight of each book

= 25.5 ÷ 1.25

= 20.4 books

because having 0.4 of a book (i.e part of a book) would not be very feasable, we have to round the number of books down to the nearest whole number)

20.4 books rounded down to nearest whole number = 20 books (answer)

5 0
2 years ago
Read 2 more answers
1/2 s + 3/4 s + 1/4 s + 4
Doss [256]

1/2 s + 3/4 s + 1/4 s + 4

((2+3+1)/4)s +4

6/4 s + 4

3/2 s + 4

4 0
3 years ago
Read 2 more answers
write a function g whose graph represents a translation 2 units to the right followed by a horizontal stretch by a factor or 2 o
Alenkinab [10]
\bf f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}\\\\
f(x)=&{{  A}} \left|{{ B }}x+{{  C}}  \right|+{{  D}}
\\\\
--------------------\\\\

\bf \bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}\\
\left. \qquad   \right.  \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{  B}}\textit{ is negative}\\
\left. \qquad   \right.  \textit{reflection over the y-axis}

\bf \bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{  D}}\\
\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\
\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}

with that template in mind, let's see,
 
\bf f(x)=|x| \implies \begin{array}{lllccll}
f(x)=&1|&1x&+0|&+0\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}

so, to shift it to the right by 2 units, simply set C = 2.
to stretch it by 2, set A = 1/2.

the smaller A is, the wider it opens, the larger it is, the more it shrinks.
5 0
3 years ago
Need help will give 15 points
Fantom [35]

Answer:

y = -2/3x + 6

Step-by-step explanation:

To find the slope, find how much y changes in proportion to x. Here, when x changes by 1, y changes by -2/3. So, the number before x is -2/3.

To find the y-intercept, we need to find what y will be when x is 0. Since we know that when x is 1, y is 16/3, and when x decreases by 1, y increases by 2/3. So, when x is 0, y is 16/3 + 2/3, which is 18/3, or 6.

5 0
3 years ago
Put these numbers in order from least to greatest.<br> -1, 21/28, -22/25
jek_recluse [69]

Answer:

-22/55,-1,21/28

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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