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miskamm [114]
2 years ago
11

Find the area and please show the steps and explain. Thanks!

Mathematics
1 answer:
Anit [1.1K]2 years ago
3 0
I'm pretty sure you just add all the numbers up so it would be 569.9 ft 
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What is 1 and 1/2 worth
koban [17]
1 is a whole and 1/2 is just a fraction

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3 years ago
Simplify the algebraic expression -5(6x)
WINSTONCH [101]

Answer:

-30x

Step-by-step explanation:

The parenthesis is just to multiply, and you can combine like terms. So -5*6=-30, which you multiply with x to get -30x.

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The figure shows a pair of parallel line segments on a coordinate grid:
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2 years ago
Read 2 more answers
Scott and Ariel want to make as much as snack mix as possible, but no more than 25 cups of mix. I they can use only full cups of
photoshop1234 [79]

Answer:

hello your question has some missing parts attached below is the missing information

answer : Scott will make 5 snack mix without going over

Step-by-step explanation:

Given that:

Scott makes a snack  mix with ; 2 cups of Almonds and 3 cups of raisins

=  5cups per snacks mix

Ariel makes a snack mix with : 3 cups of almonds and 5 cups of sunflower seeds = 8 cups per snack mix

<u>Now back to your question above</u>

Given that : No more than 25  full cups is required to make a snack mix

For Scott

= 25 / 5 = 5 snack mix ( No make overs )

For Ariel

= 25 / 8 = 3.125 snack mix ( there is a makeover of 0.125 )

Hence it can be said that Scott will make the most mix without going over

8 0
3 years ago
construct a polynomial function with the stated properties. third degree with zeros of -2,-1, and 3 and passes through the point
AfilCa [17]

Answer:

f(x) =  - (x + 2)(x + 1)(x - 3)

Step-by-step explanation:

Let f(x) be the 3rd degree polynomial function.

The roots of this function are:

x=-2, x=-1 and x=3.

The factored form is:

f(x) = a(x + 2)(x + 1)(x - 3)

This equation passes through (2,12)

This implies that;

a(2 + 2)(2+ 1)(2 - 3) = 12 \\  - 12a = 12 \\ a =  - 1

The polynomial function is

f(x) =  - (x + 2)(x + 1)(x - 3)

3 0
3 years ago
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