Write the following equation in standard form: x^5 + 2x^3 +6x + 1/5

Mathematics

1 answer:

Stella [2.4K]3 years ago

3 0

Or use photomath, it is also useful!

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how will the motion of the ball with greater mass be different from the motion of the ball with less mass

zepelin [54]

Answer:

The object with greater mass will experience a need of a greater force to accommodate the same distance that could be travelled by the lighter mass.

Step-by-step explanation:

Picture this scenario, I am on a see-saw with my friend Jack and he gets off then someone else join on his side where he was, but that person is a little heavier. I cannot simply use the same force that I used with Jack. Why? because simply I won't get the same work done. i.e reach up high in the sky. Hope this helps bud!

6 0

3 years ago

Please help me with the below question.

o-na [289]

Given that

$\vec r(t) = \left\langle 4t e^{-t}, 8 \arctan(t), 8 e^t \right\rangle$

we first differentiate with respect to t to get the tangent vector, $\vec T(t)$ :

$\vec T(t) = \dfrac{d\vec r}{dt} = \left\langle (4-4t) e^{-t}, \dfrac8{1+t^2}, 8e^t \right\rangle$

At t = 0, the tangent vector is

$\vec T(0) = \left\langle 4, 8, 8 \right\rangle$

To get the <em>unit</em> tangent vector, multiply this by 1/(norm of tangent vector) :

$\|\vec T(0)\| = \sqrt{4^2 + 8^2 + 8^2} = \sqrt{144} = 12$

Then the unit tangent vector is

$\dfrac{\vec T(0)}{\|\vec T(0)\|} = \left\langle \dfrac4{12}, \dfrac8{12}, \dfrac8{12}\right\rangle = \boxed{\left\langle\dfrac13, \dfrac23, \dfrac23\right\rangle}$