<span>ax^2+bx+c
x^2-4x+3
(x-3)(x-1)=0
x=3, x=1 when y=0
The graph of the parabola has a minimum because a is positive.
(3+1)/2=2 so y will be at a minimum when x=2
f(x)=y=2^2-(4*2)+3
=4-8+3</span>
A 270° counterclockwise rotation leads to this transformation:
(x,y) → (y, - x)
So, we have
original point new point
J (-6,2) → J' (2,6)
K (-4,6) → K' (6,4)
L (-3,3) → L' (3,3)
M (-5,-1) → M' (-1,5)
So, you have the points J', K', L', and M' that define the new parallelogram.
Answer: The coordinates of the endpoints of the side congruent to side KL are the coordinates of K' and L' which are (6,4) and (3,3).
Yes.
First, you find the fractions with common denominators: 9/10 is equal to 72/80 and 6/8 is equal to 60/80.
Since 72 is greater than 60, 9/10 is greater than 6/8.
What shaded region? Was there supposed to be a pic?
The new price after a 5% reduction would be $9,716.6
