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3 years ago

Please I need help ASAP

Mathematics

1 answer:

kondor19780726 [428]3 years ago

7 0

Answer: 120 shrimp in a 5 pound bag.

Step-by-step explanation: For every pound there is 24 shrimp, so 2 pounds is 48

24+24=48

48+24=72

72+24=86

The equation should be 24 x 5= 120

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If the area of the trapezoid below is 98 square units,what is the value of x?<br>Plz help!

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Find the value of x. A triangle has 180 degrees.

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To avoid detection at customs, a traveler has placed 6 narcotic tablets in an Urn containing 9 vitamin pills that are similar in

Alexus [3.1K]

Answer:

$\frac{4}{91}$

Step-by-step explanation:

We are told that to avoid detection at customs, a traveler has placed 6 narcotic tablets in an Urn containing 9 vitamin pills that are similar in appearance.

To find the probability that the traveler will be arrested for illegal possession of narcotics we will use theoretical probability formula.

$\text{Probability}=\frac{\text{Number of favorable outcomes}}{\text{Number of possible outcomes}}$

Favorable outcomes will be $_{3}^{6}\textrm{C}$ .

$\text{Favorable outcomes}=_{3}^{6}\textrm{C}=\frac{6!}{(6-3)!3!}$

$\text{Favorable outcomes}=\frac{6!}{3!3!}$

$\text{Favorable outcomes}=\frac{6\cdot 5\cdot 4\cdot3!}{3\cdot 2\cdot 1\cdot3!}$

$\text{Favorable outcomes}=\frac{6\cdot 5\cdot 4}{3\cdot 2}$

$\text{Favorable outcomes}=5\cdot 4=20$

Now let us find number of possible outcomes.

$\text{Number of possible outcomes}=_{3}^{15}\textrm{C}=\frac{15!}{(15-3)!3!}$

$\text{Number of possible outcomes}=\frac{15!}{12!3!}$

$\text{Number of possible outcomes}=\frac{15\cdot 14\cdot 13\cdot 12!}{12!\cdot 3\cdot 2\cdot 1}$

$\text{Number of possible outcomes}=\frac{15\cdot 14\cdot 13}{ 3\cdot 2\cdot 1}$

$\text{Number of possible outcomes}=5\cdot 7\cdot 13=455$

Upon substituting our values in probability formula we will get,

$\text{Probability that the traveler will be arrested for illegal possession of narcotics}=\frac{20}{455}$

Upon dividing numerator and denominator by 5 we will get,

$\text{Probability that the traveler will be arrested for illegal possession of narcotics}=\frac{4}{91}$

Therefore, the probability that the traveler will be arrested for illegal possession of narcotics is $\frac{4}{91}$ .

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3 years ago