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3 years ago

Please help me in this and I’ll mark you BRAINYLEST

Mathematics

2 answers:

Mashutka [201]3 years ago

6 0

Answer:

12x^7

Step-by-step explanation:

3x^2(4)x^5

=3*x^2*4*x^5

=12*x^7

=12x^7

Please give brainlist!

saw5 [17]3 years ago

4 0

Step-by-step explanation:

Given

$3 {x}^{2} \times 4 {x}^{5} \\ = 12 {x}^{2 + 5} \\ = 12 {x}^{7}$

Hope it will help :)❤

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In the figure, AB || CD and mZ2 = 55°.

Travka [436]

Answer:

m <2=m <8(Alternative exterior angles)

Therefore m <8=55°

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2 years ago

Select the correct answer.<br> The area of a square is 9 square feet as shown below

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The answer to the problem is A

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3 years ago

What is the equation of the line that passes through (-2, 2) and (1, -4)?

poizon [28]

Answer:

y = - 2x - 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ = (- 2, 2) and (x₂, y₂ ) = (1, - 4)

m = $\frac{-4-2}{1+2}$ = $\frac{-6}{3}$ = - 2, thus

y = - 2x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

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3 0

3 years ago

Question 4

polet [3.4K]

Answer:

12/7 hours

Step-by-step explanation:

First find the rate for hour for the two. For Lianne she can do 1/3 of the job per hour. For Julie she can do 1/4 of the job per hour.

Adding them together, 1/3+1/4= 7/12.

This 7/12 means that working together they can finish 7/12 of a job in an hour. We can use the speed*time=distance formula here and see that

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2 years ago

1.) Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth .x squared minus 21 x equals n

Andrew [12]

Part 1
We are given $x^2-21x=-4x$ . This can be rewritten as $x^2-18x=0$ .
Therefore, a=1, b=-18, c=0.
Using the quadratic formula
$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}=\frac{-\left(-18\right)\pm \sqrt{\left(-18\right)^2-4\left(1\right)\left(0\right)}}{2\left(1\right)}$
$x=\frac{18\pm 18}{2}$

The values of x are
$x_1=\frac{18-18}{2}=0$
$x_2=\frac{18+18}{2}=18$

Part 2
Since the values of y change drastically for every equal interval of x, the function cannot be linear. Therefore, the kind of function that best suits the given pairs is a quadratic function.

Part 3.
The first equation is $y=x^2+2$ .
The second equation is $y=3x+20$ .

We have
$x^2+2=3x+20$
$x^2-3x-18=0$
Factoring, we have
$\left(x-6\right)\left(x+3\right)=0$
Equating both factors to zero.
$x_1-6=0\rightarrow x_1=6$
$x_2+3=0\rightarrow x_2=-3$

When the value of x is 6, the value of y is
$y=3\left(6\right)+20=38$

When the value of x is -3, the value of y is
$y=3\left(-3\right)+20=11$

Therefore, the solutions are (6,38) or (-3,11)

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3 years ago