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Mariana [72]
2 years ago
7

The base of a ladder is 2.8m placed away from a tree that is 4.5m tall. The end of the ladder touches the top of the tree. Calcu

late the length of the ladder.
Mathematics
1 answer:
horrorfan [7]2 years ago
4 0

Step-by-step explanation:

Hello all beautiful your day

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nancy spent 7/8 hour working out at the gym she spent 5/7 of that time lifting weights what fraction of an hour did sje spentld
Juli2301 [7.4K]

\frac{9}{56}\\ Fraction of hour was spent by NAncy in lifting weights

Step-by-step explanation:

Time spent at the gym by Nancy = \frac{7}{8}\,hour

Time spent at lifting weights =  \frac{5}{7}\,hour

What fraction of hour she spent in lifting weights?

Solving:

Fraction of hour she spent in lifting weights= Time spend at the gym-Time spent at lifting weights

Fraction of hour she spent in lifting weights=\frac{7}{8}\,hour-\frac{5}{7}\,hour

=\frac{49}{56}-\frac{40}{56}\\=\frac{49-40}{56}\\=\frac{9}{56}\\

So, \frac{9}{56}\\ Fraction of hour was spent by Nancy in lifting weights

Keywords: Word Problems involving Fractions

Learn more about Word Problems involving Fractions at:

  • brainly.com/question/1648978
  • brainly.com/question/1677114
  • brainly.com/question/605571

#learnwithBrainly

7 0
2 years ago
John Sells Hamburgers For $3 Each and cheeseburgers for $3.50 each. One afternoon, he sells a total of 24 burgers for $79. How M
Alexxx [7]
Let the hamburgers be x and cheese burgers be y.

x + y = 24
3x + 3.5 y = 79

x = 24 - y.

Substituting the value of x,

3( 24 - y) + 3.5 y = 79

 72- 3y + 3.5 y = 79
72 + 0.5 y = 79

0.5y = 79 - 72 = 7
1/2 y = 7

thus, y = 7 * 2 = 14

Substituting the value for x,

x + y = 24
x + 14 = 24
x = 24-14 = 10
Thus, x = 10.

Thus, she sold 10 hamburgers and 14 cheeseburgers 
4 0
3 years ago
The graph of f(x) is shown. Estimate f(-3).<br> f(-3) = 1
Effectus [21]

Answer:

There is no graph.

But 1 would be a good estimate if f(-3)=1

Step-by-step explanation:

5 0
3 years ago
Which of the following trigonometric inequalities has no solution over the interval 0 ≤ x ≤ 2pi radians?
valentinak56 [21]

Answer:

A .cos(x)<1

Step-by-step explanation:

According to the first inequality

cos(x)<1

x < arccos 1

x<0

This therefore does not have a solution within the range 0 ≤ x ≤ 2pi

x cannot be leas than 0. According to the range not value, 0≤x which is equivalent to x≥0. Thus means otvis either x = 0 or x> 0.

For the second option

.cos(x/2)<1

x/2< arccos1

x/2<0

x<0

This inequality also has solution within the range 0 ≤ x ≤ 2pi since 0 falls within the range of values.

For the inequality csc(x)<1

1/sin(x) < 1

1< sin(x)

sinx>1

x>arcsin1

x>90°

x>π/2

This inequality also has solution within the range 0 ≤ x ≤ 2pi since π/2 falls within the range of values

For the inequality csc(x/2)<1

1/sin(x/2) < 1

1< sin(x/2)

sin(x/2)> 1

x/2 > arcsin1

X/2 > 90°

x>180°

x>π

This value of x also has a solution within the range.

Therefore option A is the only inequality that does not have a solution with the range.

6 0
3 years ago
Can somebody help me do this, please
natta225 [31]

Step-by-step explanation:

For the triangle on the bottom right the missing angle is

180- (74+50)= 56°

For the triangle on the bottom left the missing angle is

180- (45+80)= 55°

For the triangle in the middle the missing angle is

180- (54+51)= 75°

For the triangle on top the missing angle is

180- (80+54)= 46°

180- (74+51)= 55°

180- (46+55)= 79°

3 0
2 years ago
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