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3 years ago

Can somebody please help me with this asapp please .

Mathematics

1 answer:

yan [13]3 years ago

4 0

Answer:

Step-by-step explanation:

8x6 is 48

7x6 is 42

so 5x6 is 30

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Suppose approximately 75% of all marketing personnel are extroverts, whereas about 70% of all computer programmers are introvert

Setler [38]

Answer:

$P(x \ge 5) = 1.000$ ---- At least 5 from marketing departments are extroverts

$P(x=15) = 0.013$ ---- All from marketing departments are extroverts

$P(x = 0) = 0.002$ ---------- None from computer programmers are introverts

Step-by-step explanation:

See comment for complete question

The question is an illustration of binomial probability where

$P(x) = ^nC_x * p^x * (1 - p)^{n-x}$

$(a):\ P(x \ge 5)$

$n = 15$ --- marketing personnel

$p = 75\%$ --- proportion that are extroverts

Using the complement rule, we have:

$P(x \ge 5) = 1 - P(x < 5)$

So, we have:

$P(x < 5) =P(x = 0) + P(x = 1) + P(x = 2) + P(x = 3) + P(x = 4)$

$P(x = 0) = ^{15}C_{0} * (75\%)^0 * (1 - 75\%)^{15 - 0} = 1 * 1 * (0.25)^{15} = 9.31 * 10^{-10}$

$P(x = 1) = ^{15}C_{1} * (75\%)^1 * (1 - 75\%)^{15 - 1} = 15* (0.75)^1 * (0.25)^{14} = 4.19 * 10^{-8}$

$P(x = 2) = ^{15}C_{2} * (75\%)^2 * (1 - 75\%)^{15 - 2} = 105* (0.75)^2 * (0.25)^{13} = 8.80 * 10^{-7}$

$P(x = 3) = ^{15}C_{3} * (75\%)^3 * (1 - 75\%)^{15 - 3} = 455* (0.75)^2 * (0.25)^{12} = 0.0000153$

$P(x = 4) = ^{15}C_{4} * (75\%)^4 * (1 - 75\%)^{15 - 4} = 1365 * (0.75)^4 * (0.25)^{11} = 0.000103$

So, we have:

$P(x < 5) = (9.31 * 10^{-10}) + (4.19 * 10^{-8}) + (8.80 * 10^{-7}) + 0.0000153 + 0.000103$

$P(x < 5) = 0.00011922283$

Recall that:

$P(x \ge 5) = 1 - P(x < 5)$

$P(x \ge 5) = 1 - 0.00011922283$

$P(x \ge 5) = 0.9998$

$P(x \ge 5) = 1.000$ --- approximated

$(b)\ P(x = 15)$

$n = 15$ --- marketing personnel

$p = 75\%$ --- proportion that are extroverts

So, we have:

$P(x) = ^nC_x * p^x * (1 - p)^{n-x}$

$P(x=15) = ^{15}C_{15} * 0.75^{15} * (1 - 0.75)^{15-15}$

$P(x=15) = 1 * 0.75^{15} * (0.25)^{0$

$P(x=15) = 0.013$

$(c)\ P(x = 0)$

$n=5$ ---------- computer programmers

$p = 70\%$ --- proportion that are introverts

So, we have:

$P(x) = ^nC_x * p^x * (1 - p)^{n-x}$

$P(x = 0) = ^{5}C_0 * (70\%)^0 * (1 - 70\%)^{5-0}$

$P(x = 0) = 1 * 1 * (0.30)^5$

$P(x = 0) = 0.002$

3 0

2 years ago

Answer pleaseeeeeeeeeee

kondaur [170]

Answer:

B. $10 bag, $0.80 per pound

Step-by-step explanation:

10 / 8 = 0.80

25 / 15 = 1.67

0.80 is cheaper

7 0

3 years ago

Read 2 more answers

Sum term product factor quotients coefficients for 5x+12

Svetllana [295]

I tried I hope this helps in any kind of way

4 0

3 years ago

What is the value if the expression 6+18÷3×4

Liula [17]

In the order of PEMDAS
the first thing you would do is divide 18/3 = 6
then multiply 6 x 4 = 24
then add 24 + 6 = 30

8 0

3 years ago

Read 2 more answers

Which is the equation of a parabola with a directrix at y = −3 and a focus at (5, 3)? y = one twelfth(x − 5^)2

ankoles [38]

The equation of a parabola with a directrix at y = -3 and a focus at (5 , 3) is y = one twelfth (x - 5)² ⇒ 1st answer

Step-by-step explanation:

The form of the equation of the parabola is (x - h)² = 4p(y - k), where

The vertex of the parabola is (h , k)
The focus is (h , k + p)
The directrix is at y = k - p

∵ The focus of the parabola is at (5 , 3)

- Compare it with the 2nd rule above

∴ h = 5

∴ k + p = 3 ⇒ (1)

∵ The directrix is at y = -3

- By using the 3rd rule above

∴ k - p = -3 ⇒ (2)

Solve the system of equations to find k and p

Add equations (1) and (2) to eliminate p

∴ 2k = 0

- Divide both sides by 2

∴ k = 0

- Substitute the value of k in equation (1) to find p

∵ 0 + p = 3

∴ p = 3

Substitute the values of h , k , and p in the form of the equation above

∵ (x - 5)² = 4(3)(y - 0)

∴ (x - 5)² = 12 y

- Divide both sides by 12

∴ $\frac{1}{12}$ (x - 5)² = y

- Switch the two sides

∴ y = $\frac{1}{12}$ (x - 5)²

The equation of a parabola with a directrix at y = -3 and a focus at (5 , 3) is y = $\frac{1}{12}$ (x - 5)²

Learn more:

you can learn more about the quadratic equations in brainly.com/question/8054589

#LearnwithBrainly

8 0

3 years ago