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liberstina [14]
2 years ago
10

Find the length of AB. help asap !!!

Mathematics
1 answer:
Stella [2.4K]2 years ago
3 0

Answer:

AB = sqrt 74 = 8.602

Step-by-step explanation:

simple:

a^2+b^2=c^2

5^2+7^2=74

ab=sqrt 74

Formula :

Distance between two points = √(xB−xA)2+(yB−yA)2(xB-xA)2+(yB-yA)2

Solution :

Distance between two points = √(8−3)2+(2−9)2(8-3)2+(2-9)2

= √52+(−7)252+(-7)2

= √25+4925+49

= √7474 = 8.6023

Distance between points (3, 9) and (8, 2) is 8.6023

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Simplify each of the expression (x-7)(x+3)
emmainna [20.7K]

Answer:

x² - 10x + 21

Step-by-step explanation:

yw

4 0
2 years ago
Ray has found that his new car gets 31 miles per gallon on the highwayand 26 miles per gallon in the city. He recently drove 285
Mkey [24]

Answer:

Highway = 155\ miles

City = 130\ miles

Step-by-step explanation:

Given

Highway = 31mi/gallon

City = 26mi/gallon

Total\ Miles = 285

Total\ Gallons = 10

Required

Determine the number of miles driven on the highway and on the city

Represent the gallons used on highway with h and on city with c.

So, we have:

c + h = 10 ---- gallons used

and

31h + 26c = 285 --- distance travelled

In the first equation, make c the subject

c = 10 - h

Substitute 10 - h for c in the second equation

31h + 26c = 285

31h + 26(10 - h) = 285

Open bracket

31h + 260 - 26h = 285

Collect like terms

31h - 26h = 285 - 260

5h = 25

Make h the subject

h = \frac{25}{5}

h = 5

Substitute 5 for h in c = 10 - h

c = 10 - 5

c = 5

If on the highway, he travels 31 miles per gallon, then his distance on the highway is:

Highway = 31 * 5

Highway = 155\ miles

If in the highway, he travels 26 miles per gallon, then his distance on the highway is:

City = 26 * 5

City = 130\ miles

8 0
3 years ago
-3x - y = 15<br> y = -8x<br> (x, y) = (0<br> )<br> 9,0
Nataly [62]
<h3>The solution is (x, y) = (3, -24)</h3>

<em><u>Solution:</u></em>

<em><u>Given system of equations are:</u></em>

-3x - y = 15 -------- eqn 1

y = -8x ------ eqn 2

We have to find solution of (x, y)

We can solve by substitution method

<em><u>Substitute eqn 2 in eqn 1</u></em>

-3x - (-8x) = 15

-3x + 8x = 15

5x = 15

Divide both sides by 5

<h3>x = 3</h3>

Substitute x = 3 in eqn 2

y = -8(3)

<h3>y = -24</h3>

Thus solution is (x, y) = (3, -24)

4 0
3 years ago
How many solutions are there to the equation below?
bezimeni [28]

A square root cannot be equl to a negative.


answer: C. 0

6 0
2 years ago
What is the solution to this inequality -13x&gt; - 39
s344n2d4d5 [400]

Answer:

Isolate the variable by dividing each side by factors that don't contain the variable.

Inequality Form:  x < 3

Interval Notation:

( − ∞ , 3 )

3 0
3 years ago
Read 2 more answers
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