<span> a⁴(3a² - 2a + 1)
We just have to multiply each term inside the parentheses by a⁴ .
a⁴</span><span>(3a² ) = 3a⁶
a⁴</span><span>( - 2a ) = -2a⁵
a⁴</span><span>( 1) = a⁴
Now, just addum up : 3a⁶ - 2a⁵ + a⁴</span>
Answer:
It is, D
Step-by-step explanation:
Your welcome for raising your test score
Answer:
0, for q ≠ 0 and q ≠ 1
Step-by-step explanation:
Assuming q ≠ 0, you want to find the value of x such that ...
q^x = 1
This is solved using logarithms.
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x·log(q) = log(1) = 0
The zero product rule tells us this will have two solutions:
x = 0
log(q) = 0 ⇒ q = 1
If q is not 0 or 1, then its value is 1 when raised to the 0 power. If q is 1, then its value will be 1 when raised to <em>any</em> power.
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<em>Additional comment</em>
The applicable rule of logarithms is ...
log(a^b) = b·log(a)
The answer would b C. 1,208 ft2
Answer:
3^(n+1) - 3^n / 3^(n-1) = 6
