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Oxana [17]
4 years ago
5

In how many ways can 4 different contracts be distributed among 12 different firms, if no two contracts are awarded to the same

firm?
Mathematics
1 answer:
vagabundo [1.1K]4 years ago
5 0

The first contract can go to any of 12 firms. The second can go to any of the remaining 11 firms, and so on. Finally, the 4th contract can go to any of the 9 firms that don't yet have a contract.

The number of ways the contracts can be awarded is

... 12×11×10×9 = 11,880

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Hope this helped!

-------------------------------

DISCLAIMER: I am not a professional tutor or have any professional background in your subject. Please do not copy my work down, as that will only make things harder for you in the long run. Take the time to really understand this, and it'll make future problems easier. I am human, and may make mistakes, despite my best efforts. Again, I possess no professional background in your subject, so anything you do with my help will be your responsibility. Thank you for reading this, and have a wonderful day/night!
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