Answer:
B. No the ordered pair does not satisfy the equation
Step-by-step explanation:
y = -9x - 2
Substitute the point in and see if it is true
-37 = -9(4) -2
-37 = -36 -2
-37 = -38
This is not true so the point is not a solution
S = sale price (in dollars)
p = sticker price (in dollars)
Note: the sticker price is what the customer pays after the discount
Another note: This is ignoring any taxes or other fees
We're told that the sale price is the result of taking 10% off the sticker price. This means...
sale price = (sticker price) - (10% of sticker price)
s = p - 0.10*p
s = 1*p - 0.10*p
s = (1 - 0.10)*p
s = (0.90)*p
s = 0.90*p
So the expression for the sale price is 0.90*p where p is the sticker price in dollars.
Note: this means that the sale price is 90% of the sticker price.
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Now plug in the sticker price p = 80 to find the sale price s
s = 0.90*p
s = 0.90*80
s = 72
The sale price is $72 which is what the customer will pay (if we ignore any taxes or other fees).
2 to the first is 2 because there is only one 2
Answer: 6/12 are white, 3/12 are colored and 3/12 are albino.
Step-by-step explanation: If the horses are white and their parents are ccww (albino) and CCWw (white horse), according to Mendel's premises, they both must be CcWw, since the crossing provides one C from one parent and other c from the other parent, one W and the other w. Using Mendel's chess and the principle of independent segregation, the crossing between CcWw results in the following fenotypical ratio:
1/16 CCWW (lethal)
2/16 CCWw (white)
2/16 CcWW (lethal)
4/16 CcWw (white)
1/16 CCww (normal)
2/16 Ccww (normal)
2/16 ccWw (albino)
1/16 ccWW (lethal)
1/16 ccww (albino)
Excluding the 4 individuals that have the lethal locus, we have 6/12 that are white (2/12 + 4/12) and 3/12 (1/12 + 2/12) that are colored. Also, there are 3/12 of albino individuals as well.