Answer:
I'm gonna use the distance formula:
Distance = sqrt((x2-x1)^2 + (y2-y1)^2)
Distance = sqrt((6-3)^2 + (13-9)^2)
Distance = sqrt(3^2 + 4^2)
Distance = sqrt(9 + 16)
Distance = sqrt(25)
Distance = 5
The problem says every unit = 1 mile so 5 units = 5 miles.
Answer = 5 miles
Step-by-step explanation:
Add 20$ and 25$ and go along the line while adding 25 each time, at the same time do the same for 35$, the answer is the second month
Answer:
5) y = 3x + 1
6) For this question, I would just draw a line that is increasing, and then once it reaches 10 mins I would make a steep line going downward. Something like this: /\
7) Yes, Raoul is correct because Function A's initial value is 0 and function B's initial value is 3.
Answer:
sorry if im reading it wrong but...whats the question here??
Step-by-step explanation:
Answer:
![\large\boxed{\dfrac{2-\frac{1}{y}}{3+\frac{1}{y}}=\dfrac{2y-1}{3y+1}}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B%5Cdfrac%7B2-%5Cfrac%7B1%7D%7By%7D%7D%7B3%2B%5Cfrac%7B1%7D%7By%7D%7D%3D%5Cdfrac%7B2y-1%7D%7B3y%2B1%7D%7D)
Step-by-step explanation:
![\dfrac{2-\frac{1}{y}}{3+\frac{1}{y}}=\left(\dfrac{2y}{y}-\dfrac{1}{y}\right):\left(\dfrac{3y}{y}+\dfrac{1}{y}\right)=\dfrac{2y-1}{y}:\dfrac{3y+1}{y}=\dfrac{2y-1}{y}\cdot\dfrac{y}{3y+1}\\\\=\dfrac{2y-1}{3y+1}](https://tex.z-dn.net/?f=%5Cdfrac%7B2-%5Cfrac%7B1%7D%7By%7D%7D%7B3%2B%5Cfrac%7B1%7D%7By%7D%7D%3D%5Cleft%28%5Cdfrac%7B2y%7D%7By%7D-%5Cdfrac%7B1%7D%7By%7D%5Cright%29%3A%5Cleft%28%5Cdfrac%7B3y%7D%7By%7D%2B%5Cdfrac%7B1%7D%7By%7D%5Cright%29%3D%5Cdfrac%7B2y-1%7D%7By%7D%3A%5Cdfrac%7B3y%2B1%7D%7By%7D%3D%5Cdfrac%7B2y-1%7D%7By%7D%5Ccdot%5Cdfrac%7By%7D%7B3y%2B1%7D%5C%5C%5C%5C%3D%5Cdfrac%7B2y-1%7D%7B3y%2B1%7D)