It is one of the beginning compounds.
This is the answer for many reasons. First off, it is not one of the ending compounds. It is only the end compound for photosynthesis. Second, it does not react to water as that is yet again photosynthesis. It does not react with carbon dioxide as carbon dioxide is what initially creates oxygen within cellular respiration.
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Answer:
(A) It prevents electron flow from the iron-sulfur centers in complex 1 to the ubiquinone. Due to reduction in electron transfer rate, there is a decrease in the production of ATP which is dangerous for some insects and fish over time.
(B) It also prevents electron flow from cytochrome b to cytochrome c1 at the complex III which leads to QH2 accumulation. If oxidized Q is not present, these is alteration of electron flow and the production of ATP is altered.
(C) Rotenone only prevent electron transfer into the chain at Complex 1 but it does not affect electron transfer at Complex II. Although there is slow ETC, it does not stop completely. However, Antimycin A prevents the oxidation of QH2, the final electron acceptor crom complex I and complex II. Thereby, stopping the production of both ETC and ATP. It can be concluded that antimycin A is a more potent poison.
Explanation:
Rotenone prevents electron flow from the iron-sulfur centers in complex 1 to the ubiquinone. Due to a reduction in electron transfer rate, there is a decrease in the production of ATP which is dangerous for some insects and fish over time. Antimycin A also prevents electron flow from cytochrome b to cytochrome c1 at the complex III which leads to QH2 accumulation. If oxidized Q is not present, there is an alteration of electron flow and the production of ATP is altered. Antimycin A is more potent than rotenone.
I think it is light so B) light
Answer:
The correct answer is option D) "K".
Explanation:
In this example the wolf population is described by the equation "ΔN/Δt=rN(K−N)K". Even tough the variables are not defined in the question, we can conclude that the effect of the moose population will be given by a factor that has a positive effect in the wolf's population because "as moose populations increase, wolf populations also increase". The factor "K" fits the description because it gives a positive effect on "ΔN/Δt". "K" is a factor that multiplies "rN" at two different levels, therefore the higher the value of "K", the higher value of "ΔN/Δt" will be.
