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3 years ago

A box has a volume given by the trinomial x^3 + 4x^2 — 32x. What are the possible dimensions of the box?

Mathematics

1 answer:

Luden [163]3 years ago

5 0

Answer:

x(x-4)(x+8)

Step-by-step explanation:

Factor.

x(x^2+4x-32)

x(x-4)(x+8)

You might be interested in

Write a linear function f with the values F (0) = 4 and F (3) = -8

REY [17]

The answer to this is
Y = -4x + 4

7 0

3 years ago

Solve using substitution: 2x - 3y = -1 y = x - 1

denis-greek [22]

Answer:

x=4 y=3

Step-by-step explanation:

rewrite the equations- y=x-1 2x-3y=-1

solve y=x-1 for y

y=x-1

sub for x-1 for y in 2x-3y=-1

2x-3y=-1

2x-3(x-1)=-1

-x+3=-1

-x+3+-3=-1+-3

-x=-4

divide both sides by -4

x=4

sub 4 for x in y=x-1

y=x-1

y=4-1

y=3

WE ARE VENOM

8 0

3 years ago

PLEASE HELP ME ASAP I'M HORRIBLE AT MATH

boyakko [2]

Answer:

Simple, 2.4

Step-by-step explanation:

anything with N or X on the side of a number means to multiply, and 2.4*15= 36, all you need to use is the opposite of it, aka, division. 15*__=36

If possible; brainliest?

7 0

3 years ago

Read 2 more answers

We usually Round off the 79.90% to 80. What value does 80 count?

pochemuha

Answer: 00.10

Step-by-step explanation: Add 00.10 to 79.90 and you get 80. Brainliest please?

4 0

3 years ago

I need help solving this plz

Mamont248 [21]

We can rewrite $cot(45^{\circ}+2\theta)$ as $tan(90^{\circ}-(45^{\circ}+2\theta)$ $\Rightarrow$ $cot(45^{\circ}+2\theta)$ equals to $tan(45^{\circ}-2\theta)$ .

Now we need to take an $arctan$ of both sides.

$\theta = 45^{\circ}-2\theta+180n^{\circ}
\\3\theta = 180n^{\circ}+45^{\circ}
\\\theta = 60n^{\circ}+15^{\circ}
\\\theta = 15^{\circ}$

Your answer is $15^{\circ}$ .

8 0

4 years ago