3 years ago

A box has a volume given by the trinomial x^3 + 4x^2 — 32x. What are the possible dimensions of the box?

Mathematics

1 answer:

Luden [163]3 years ago

5 0

Answer:

x(x-4)(x+8)

Step-by-step explanation:

Factor.

x(x^2+4x-32)

x(x-4)(x+8)

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bezimeni [28]

Answer:

26-4s=9s

26-(4s-9s)=0

26+5s=0

5s=-26

ans: s= -26/5

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18r=18

ans: r=1

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-13t=-78

13t=78

ans: t=26

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