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Sliva [168]
3 years ago
11

The principal of a school claims that 30 % of grade 3 pupils stay in the playground after their classes. A survey among 500 grad

e 3 pupils revealed that 150 of them stay in the playground after their classes. Use 99% confidence to conduct a test of proportions.
No unrelated answers or links or you will be reported. Thanks​
Mathematics
1 answer:
ycow [4]3 years ago
5 0

Answer:

A survey among 500 grade 3 pupils revealed that 150 of them stayin the playground after their classes. Use 95% confidence to conduct a test of proportion. 1 1.

Step-by-step explanation:

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Question 2 help please
m_a_m_a [10]

Answer:

The measure of the vertex angle is 94 degrees ⇒ A

Step-by-step explanation:

  • In any triangle, the sum of the measures of its interior angle is 180°
  • In the isosceles triangle, the two base angles are equal in measures

∵ In an isosceles triangle, the measure of the base angle = (2x + 5)

∵ The base angles of the isosceles triangles are equal in measures

∴ The measures of the base angles are (2x + 5), (2x + 5)

∵ The measure of the vertex angle = (5x - 1)

∵ The sum of the measure of the three angles = 180°

∴ (2x + 5) + (2x + 5) + (5x - 1) = 180

→ Add the like terms in the left side

∵ (2x + 2x + 5x) + (5 + 5 + -1) = 180

∴ 9x + 9 = 180

→ Subtract 9 from both sides

∴ 9x + 9 - 9 = 180 - 9

∴ 9x = 171

→ Divide both sides by 9 to find x

∴ x = 19

→ Substitute the value of x in the measure of the vertex angle to find it

∵ The measure of the vertex angle = 5x - 1

∴ The measure of the vertex angle = 5(19) - 1

∴ The measure of the vertex angle = 95 - 1

∴ The measure of the vertex angle = 94°

∴ The measure of the vertex angle is 94 degrees

6 0
3 years ago
1.) The commuter trains on the Red Line for the Regional Transit Authority (RTA) in Cleveland, OH, have a waiting time during pe
alisha [4.7K]

Answer:

a) For this case we define the random variable as X ="waiting time during peak hours" and we know that this distribution follows an uniform distribution:

X \sim Unif(a=0,b=8)

Where a and b represent the limits of the distribution.

b) f(x) = \frac{1}{8}= 0.125, a\leq x \leq b

And the height for this case would be 0.125

Step-by-step explanation:

Part a

For this case we define the random variable as X ="waiting time during peak hours" and we know that this distribution follows an uniform distribution:

X \sim Unif(a=0,b=8)

Where a and b represent the limits of the distribution.

Part b

For this case the density function would be given by:

f(x) = \frac{1}{8}= 0.125, a\leq x \leq b

And the height for this case would be 0.125

And f(x)= 0  for other case.

The cumulative distribution function would be given by:

F(x) = 0, x

F(x) = \frac{x-a}{b-a}= \frac{x}{8}, 0\leq x < 8

F(x) = 1, x\geq 8

3 0
3 years ago
PLS HELP ILL MARK CROWN
jok3333 [9.3K]

Answer:

4x−7

Step-by-step explanation:

Being given our polynomial:

4x^{2}+ x - 14,

We must find the roots to get our answer.

x = (- 1 ± √(1 - 4*4*(-14)) / 8

x = (- 1 ± √225) / 8

x = ( -1 ± 15) / 8

x₁ = (- 1 + 15)/ 8 = 14/8 = 7 / 4

x₂ = (- 1 - 15) / 8 = - 16/2 = - 8

The factors we came up with:

(x - x₁)(x - x₂)

(x - 7/4)(x + 8)

1/4(4x - 7)(x + 8)

So,

The correct option is C.

:)

6 0
3 years ago
Read 2 more answers
What is the equation parallel to 4y-3x=8
Andreyy89

Answer:

Whatever option has a slope of 3/4 and isn't y = 3/4x + 2

Step-by-step explanation:

This means that it has to have a slope of 3/4 (written as 3/4x + b). This is because parallel lines have the same slope; rearranging the first equation gets us y = 3/4x + 2. So, our slope for a parallel line has to be 3/4.

6 0
4 years ago
Find point P that divides segments AB into a 2:3 ratio.
nasty-shy [4]
\bf ~~~~~~~~~~~~\textit{internal division of a line segment}&#10;\\\\\\&#10;A(-3,1)\qquad B(3,5)\qquad&#10;\qquad \stackrel{\textit{ratio from A to B}}{2:3}&#10;\\\\\\&#10;\cfrac{A\underline{P}}{\underline{P} B} = \cfrac{2}{3}\implies \cfrac{A}{B} = \cfrac{2}{3}\implies 3A=2B\implies 3(-3,1)=2(3,5)\\\\&#10;-------------------------------\\\\&#10;P=\left(\cfrac{\textit{sum of "x" values}}{\textit{sum of ratios}}\quad ,\quad \cfrac{\textit{sum of "y" values}}{\textit{sum of ratios}}\right)

\bf -------------------------------\\\\&#10;P=\left(\cfrac{(3\cdot -3)+(2\cdot 3)}{2+3}\quad ,\quad \cfrac{(3\cdot 1)+(2\cdot 5)}{2+3}\right)&#10;\\\\\\&#10;P=\left(\cfrac{-9+6}{5}~~,~~\cfrac{3+10}{5}  \right)\implies P=\left(-\frac{3}{5}~~,~~\frac{13}{5}  \right)
6 0
3 years ago
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