Find the product of 3x^2 and 2x+1 .

The sum of 2 consecutive numbers is 37. Find the numbers. If x represents the smaller integer, then the larger integer is

NARA [144]

Answer:

x + 1

Step-by-step explanation:

There are a few ways this problem could be solved. The easiest route is to note that the first part of the question says "2 consecutive numbers". If the numbers are next to each other on a number line (consecutive) and x is the smaller number, the larger number is x + 1.

To check, let's find the two numbers. We know the numbers are next to each other on a number line and that together, they equal 37. Let's begin with 15 and 16.

15 + 16 = 31

These numbers are too low, as they should add to 37. Let's try 18 and 19.

18 + 19 = 37

There are the two correct numbers. If x = the smaller number, x = 18.

18 + 1 = 19

Since this is correct, we know for sure that the answer is x + 1.

6 0

3 years ago

write the ratio as a fraction in simplest form, with whole numbers in the numerator and denominator. 40 to 56

masha68 [24]

Answer:

5/7

Step-by-step explanation:

A common factor of 8 can be canceled from numerator and denominator.

40/56 = (5·8)/(7·8) = (5/7)·(8/8) = (5/7)·1 = 5/7

_____

Since you know your multiplication tables, you know that 40 and 56 are both multiples of 8.

__

If you don't know your multiplication tables, you can find the greatest common divisor (GCD) of the two numbers and divide each by that. The GCD can be found using Euclid's algorithm. For that, you divide the larger by the smaller and use the remainder as the new smaller number. The original smaller number is now the larger number. For these numbers, that looks like ...

56 ÷ 40 = 1 r 16

40 ÷ 16 = 2 r 8

16 ÷ 8 = 2 r 0 . . . . . the zero remainder signals that the divisor (8) is the GCD

Now, your fraction is ...

(40/8) / (56/8) = 5/7

3 0

3 years ago

Read 2 more answers

You throw a ball up and its height h can be tracked using the equation h=2x^2-12x+20.

postnew [5]

This problem seems to be wrong because no minimum point was found and no point of landing exists

Answer:

1) There is no maximum height

2) The ball will never land

Step-by-step explanation:

Derivatives

Sometimes we need to find the maximum or minimum value of a function in a given interval. The derivative is a very handy tool for this task. We only have to compute the first derivative f' and have it equal to 0. That will give us the critical points.

Then, compute the second derivative f'' and evaluate the critical points in there. The criteria establish that

If f''(a) is positive, then x=a is a minimum

If f''(a) is negative, then x=a is a maximum

1)

The function provided in the question is

$h(x)=2x^2-12x+20$

Let's find the first derivative

$h'(x)=4x-12$

solving h'=0:

$4x-12=0$

x=3

Computing h''

h''(x)=4

It means that no matter the value of x, the second derivative is always positive, so x=3 is a minimum. The function doesn't have a local maximum or the ball will never reach a maximum height

2)

To find when will the ball land, we set h=0

$2x^2-12x+20=0$