Answer:
y = 3/2x + 15
Step-by-step explanation:
change f(x) to 'y='
interchange 'x' and 'y' then solve for 'y':
y = 2/3x - 10
x = 2/3y - 10
x+10 = 2/3y
multiply each side by 3/2 to get:
y = 3/2x + 15
Answer:
x = -10
Step-by-step explanation:
2(x + 3) = x - 4
2x + 6 = x - 4
2x - x = -4 - 6
x = -10
The values of h and k when f(x) = x^2 + 12x + 6 is in vertex form is -6 and -30
<h3>How to rewrite in vertex form?</h3>
The equation is given as:
f(x) = x^2 + 12x + 6
Rewrite as:
x^2 + 12x + 6 = 0
Subtract 6 from both sides
x^2 + 12x = -6
Take the coefficient of x
k = 12
Divide by 2
k/2 = 6
Square both sides
(k/2)^2 = 36
Add 36 to both sides of x^2 + 12x = -6
x^2 + 12x + 36= -6 + 36
Evaluate the sum
x^2 + 12x + 36= 30
Express as perfect square
(x + 6)^2 = 30
Subtract 30 from both sides
(x + 6)^2 -30 = 0
So, the equation f(x) = x^2 + 12x + 6 becomes
f(x) = (x + 6)^2 -30
A quadratic equation in vertex form is represented as:
f(x) = a(x - h)^2 + k
Where:
Vertex = (h,k)
By comparison, we have:
(h,k) = (-6,-30)
Hence, the values of h and k when f(x) = x^2 + 12x + 6 is in vertex form is -6 and -30
Read more about quadratic functions at:
brainly.com/question/1214333
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Answer:
x<120
Step-by-step explanation:
-30<x/-4
In order to simplify this, we must isolate the x value by multiplying both sides by -4
Since we are dealing with inequalities and we are multiplying by a negative number, we have to switch the sign (<,>)
-30(-4)>x
x<120
