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ICE Princess25 [194]
3 years ago
9

Find a formula for a geometric sequence that begins 100, 110, 121, .... ​

Mathematics
1 answer:
marshall27 [118]3 years ago
7 0

9514 1404 393

Answer:

  the marked choice is correct

Step-by-step explanation:

The initial term is a1 = 100. The common ratio is r = 110/100 = 1.1. The generic term is ...

  an = a1·r^(n-1)

Filling in the known parameters, we find the sequence terms sn to be ...

  \boxed{s_n=100(1.1)^{n-1}}

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<h3><u>Part A</u></h3>

\sf \rightarrow  y^2 - 3y - 4y +12

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\sf \rightarrow  y(y - 3) - 4(y - 3)

collect into groups

\sf \rightarrow  (y- 4)(y - 3)

<h3><u>Part B</u></h3>

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collect into groups

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2 years ago
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