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Sidana [21]
3 years ago
12

Express 16/6 as a mixed number

Mathematics
1 answer:
ale4655 [162]3 years ago
7 0
First you divide the numerator by the denominator, so for this it would be
16 / 6 = 2 remainder 4
so the new fraction would be
2 and 4/6 (so the remainder becomes the new numerator.
2 and 4/6 can be simplified to 
2 and 2/3
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How many 1 inch cubes do you need to create a cube with an edge length of 6 inches?
galben [10]
216 cubes. For the base, you would need 6 x 6 cubes which is 36. Since it is a cube, the height is also 6 so you multiply 36 by 6, which is 216.
6 0
3 years ago
What is 329,625 rounded to the place value of the underlined digit?
dexar [7]

Answer:

330,000

Step-by-step explanation:

if the underlined digit is 9, then the six rounds the 9 up to a 10, making the rounded number amount to 330,000.

4 0
3 years ago
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kylee bought a pack of 12 cookies. one-third if the cookies are peanut butter. How many of the cookies in the pack are peanut bu
IceJOKER [234]

Answer:

The number of packs are peanuts butter are 4 .

Step-by-step explanation:

As given

Kylee bought a pack of 12 cookies.

one-third if the cookies are peanut butter.

Thus

Number\ of\ packs\ of\ peanuts\ butter = \frac{1}{3}\times Total\ number\ of\ packs

Number\ of\ packs\ of\ peanuts\ butter = \frac{1}{3}\time 12

Number\ of\ packs\ of\ peanuts\ butter = \frac{12}{3}

Number of packs are peanut butter = 4

Therefore the number of packs are peanuts butter are 4 .

4 0
3 years ago
Read 2 more answers
You roll two fair dice, one green and one red. (a) Are the outcomes on the dice independent? Yes No (b) Find P(1 on green die an
ASHA 777 [7]

Answer:

a

  Yes

b

 P(1 \& 5) = \frac{1}{36}

c

 P(5 \& 1) = \frac{1}{36}

d

 P(5 \& 1 | 1\& 5  ) = \frac{1}{18}

Step-by-step explanation:

From the question we are told that

     Two fair dice, one green and one red were rolled

Generally the  outcomes on the dice independent because the outcome on the first dice is not affected by the second die

Generally the  probability of getting a 1  on a dice rolled is  P(1) =  \frac{1}{6}

the  probability of getting a 5 on a dice rolled is  P(5) =  \frac{1}{6}

Generally the probability of P(1 on green die and 5 on red die) is mathematically represented as

         P(1 \& 5) = \frac{1}{6}  *\frac{1}{6}

         P(1 \& 5) = \frac{1}{36}

Generally the probability of P(5 on green die and 1 on red die) is mathematically represented as

          P(5 \& 1) = \frac{1}{6}  *\frac{1}{6}

         P(5 \& 1) = \frac{1}{36}

Generally the probability of P((1 on green die and 5 on red die) or (5 on green die and 1 on red die)) is mathematically represented as

          P(5 \& 1 | 1\& 5  ) = \frac{1}{36} + \frac{1}{36}

         P(5 \& 1 | 1\& 5  ) = \frac{1}{18}

8 0
3 years ago
Evaluate the expression when a=2 and b=20
vagabundo [1.1K]
50(2) -2(20) +6 = ?
100 - 40 + 6 = ?
60 + 6 = ?
66
8 0
4 years ago
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