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o-na [289]
2 years ago
10

Mark and eight of his friends went out to

Mathematics
2 answers:
Cerrena [4.2K]2 years ago
6 0
If mark and 8 of his friends went out the total of people is 9, so if you think about it 9x9=81 so the total cost of the bill was $81
melamori03 [73]2 years ago
3 0
72 EXPLANTION 9+9+9+9+9+9+9+9+9=72
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Circumference and Area of a circle <br><br> #5 please
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It costs $15 to send 3 packages through a certain shipping company. Consider the number of packages per dollar. a. Find the cons
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x is the number of packs 3x=15$ x=5$

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marusya05 [52]

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3 years ago
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5 0
2 years ago
The number of hours worked per year per person in a state is normally distributed with a standard deviation of 39. A sample of 1
evablogger [386]

Answer:

The 98% confidence interval for the population mean number of hours worked per year per person is (2146, 2193).

Step-by-step explanation:

The question is incomplete.

The number of hours registered in the sample are:

2051 2061 2162 2167 2169 2171

2180 2183 2186 2195 2196 2198

2205 2210 2211

The sample mean can be calculated as:

M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{15}(2051+2061+2162+2167+2169+2171+2180+2183+2186+2195+2196+2198+2205+2210+2211)\\\\\\M=\dfrac{32545}{15}\\\\\\M=2169.67\\\\\\

We have to calculate a 98% confidence interval for the mean.

The population standard deviation is know and is σ=39.

The sample mean is M=2169.67.

The sample size is N=15.

As σ is known, the standard error of the mean (σM) is calculated as:

\sigma_M=\dfrac{\sigma}{\sqrt{N}}=\dfrac{39}{\sqrt{15}}=\dfrac{39}{3.873}=10.07

The z-value for a 98% confidence interval is z=2.326.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_M=2.326 \cdot 10.07=23.43

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 2169.67-23.43=2146\\\\UL=M+t \cdot s_M = 2169.67+23.43=2193

The 98% confidence interval for the population mean is (2146, 2193).

3 0
3 years ago
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