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Ilia_Sergeevich [38]
2 years ago
9

The circumference of a circle is G inches. The diameter is 15 inches. Which expression best represents the value of \piπ

Mathematics
1 answer:
oee [108]2 years ago
4 0

Answer: Try using calculatorsoup dot com, you need to be more specific, and use Find A, C and r | Given d?

radius r = 7.5 in

diameter d = 15 in

circumference C = 47.123889803847 in

area A = 176.71458676443 in2

In Terms of Pi π

circumference C = 15 π in

area A = 56.25 π in2

Step-by-step explanation:

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Please answer this question now
alisha [4.7K]

Answer:

If it's not too late by now, the answer is 19.9 mm^{2}

3 0
2 years ago
NO LINKS OR FILES!
Archy [21]

(a) If the particle's position (measured with some unit) at time <em>t</em> is given by <em>s(t)</em>, where

s(t) = \dfrac{5t}{t^2+11}\,\mathrm{units}

then the velocity at time <em>t</em>, <em>v(t)</em>, is given by the derivative of <em>s(t)</em>,

v(t) = \dfrac{\mathrm ds}{\mathrm dt} = \dfrac{5(t^2+11)-5t(2t)}{(t^2+11)^2} = \boxed{\dfrac{-5t^2+55}{(t^2+11)^2}\,\dfrac{\rm units}{\rm s}}

(b) The velocity after 3 seconds is

v(3) = \dfrac{-5\cdot3^2+55}{(3^2+11)^2} = \dfrac{1}{40}\dfrac{\rm units}{\rm s} = \boxed{0.025\dfrac{\rm units}{\rm s}}

(c) The particle is at rest when its velocity is zero:

\dfrac{-5t^2+55}{(t^2+11)^2} = 0 \implies -5t^2+55 = 0 \implies t^2 = 11 \implies t=\pm\sqrt{11}\,\mathrm s \imples t \approx \boxed{3.317\,\mathrm s}

(d) The particle is moving in the positive direction when its position is increasing, or equivalently when its velocity is positive:

\dfrac{-5t^2+55}{(t^2+11)^2} > 0 \implies -5t^2+55>0 \implies -5t^2>-55 \implies t^2 < 11 \implies |t|

In interval notation, this happens for <em>t</em> in the interval (0, √11) or approximately (0, 3.317) s.

(e) The total distance traveled is given by the definite integral,

\displaystyle \int_0^8 |v(t)|\,\mathrm dt

By definition of absolute value, we have

|v(t)| = \begin{cases}v(t) & \text{if }v(t)\ge0 \\ -v(t) & \text{if }v(t)

In part (d), we've shown that <em>v(t)</em> > 0 when -√11 < <em>t</em> < √11, so we split up the integral at <em>t</em> = √11 as

\displaystyle \int_0^8 |v(t)|\,\mathrm dt = \int_0^{\sqrt{11}}v(t)\,\mathrm dt - \int_{\sqrt{11}}^8 v(t)\,\mathrm dt

and by the fundamental theorem of calculus, since we know <em>v(t)</em> is the derivative of <em>s(t)</em>, this reduces to

s(\sqrt{11})-s(0) - s(8) + s(\sqrt{11)) = 2s(\sqrt{11})-s(0)-s(8) = \dfrac5{\sqrt{11}}-0 - \dfrac8{15} \approx 0.974\,\mathrm{units}

7 0
2 years ago
Johan sold 9 of his video games online. The next day, he sold 27 Video games. He collected a total of $900 if Johann charged the
Setler79 [48]

Answer:

$25

Step-by-step explanation:

First you would add 27 and 9 to find the total number of games he sold, next you would divide 900 by 36 to get 25, then you would do 25 times 36 to check your answer.

6 0
3 years ago
Read 2 more answers
Given O that is the center of the circle below, compare the quantity in column A with the quantity in column B.
pogonyaev

Answer:

the answer is b

Step-by-step explanation: edge 2020

4 0
2 years ago
Read 2 more answers
Suppose that, on average, electricians earn approximately μ= $54,000 per year in the united states. Assume that the distribution
11111nata11111 [884]

Answer:

0.15866.

Step-by-step explanation:

We have been given that on average, electricians earn approximately μ= $54,000 per year in the united states. Assume that the distribution for electricians' yearly earnings is normally distributed and that the standard deviation is σ= $12,000. We are asked to find the probability that the sample mean is greater than $66,000.

First of all, we will find the z-score corresponding to 66,000 using z-score formula.

z=\frac{x-\mu}{\sigma}

z=\frac{66000-54000}{12000}

z=\frac{12000}{12000}

z=1

Now, we need to find the probability that z-score is greater than 1 that is P(z>1).

Upon using formula P(z>A)=1-P(z, we will get:

P(z>1)=1-P(z

Upon using normal distribution table, we will get:

P(z>1)=1-0.84134

P(z>1)=0.15866

Therefore, the probability that the sample mean is greater than $66,000 would be 0.15866 or approximately 15.87\%.

4 0
2 years ago
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