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Stels [109]
3 years ago
13

I need some help please

Mathematics
1 answer:
weqwewe [10]3 years ago
5 0

Answer:

Switch x and y.

\frac{1}{8} (x-4)^{3}

Step-by-step explanation:

Switch the x and y, so the equation would read as:

x = \sqrt[3]{8y} +4

Then solve for y.

x = \sqrt[3]{8y} + 4\\\\\\x - 4 = \sqrt[3]{8y} \\\\\\(x-4)^{3} = 8y\\\\\\\\\\\frac{1}{8} (x-4)^{3}

#teamtrees #WAP (Water And Plant)

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