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NISA [10]
3 years ago
14

Find the necessary confidence interval for the binomial proportion p. (Round your answers to three decimal places.) A 90% confid

ence interval for p, based on a random sample of n = 400 observations from a binomial population with x = 358 successes.
Mathematics
1 answer:
frutty [35]3 years ago
5 0

Answer:

[0.875;0.925]

Step-by-step explanation:

Hello!

You have a random sample of n= 400 from a binomial population with x= 358 success.

Your variable is distributed X~Bi(n;ρ)

Since the sample is large enough you can apply the Central Limit Teorem and approximate the distribution of the sample proportion to normal

^ρ≈N(ρ;(ρ(1-ρ))/n)

And the standarization is

Z= ^ρ-ρ  ≈N(0;1)

√(ρ(1-ρ)/n)

The formula to estimate the population proportion with a Confidence Interval is

[^ρ ± Z_{1-\alpha/2}*√(^ρ(1-^ρ)/n)]

The sample proportion is calculated with the following formula:

^ρ= x/n = 358/400 = 0.895 ≅ 0.90

And the Z-value is Z_{1-\alpha/2} = Z_{0.95} = 1.648 ≅ 1.65

[0.90 ± 1.65 * √((0.90*0.10)/400)]

[0.875;0.925]

I hope you have a SUPER day!

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ExtremeBDS [4]

Answer:

  • 800 kph
  • 600 kph

Step-by-step explanation:

<u>Equation</u>

Let s represent the speed of the faster plane. Then its travel time is ...

  time = distance/speed = 3600/s

travel time for the slower plane is ...

  time = distance/speed = 3600/(s -200)

The difference in these times is 1.5 hours, so we have ...

  3600/(s -200) -3600/s = 1.5

<u>Solution</u>

Multiplying by (2/3)s(s -200), we get ...

  2400(s) -2400(s -200) = s(s -200)

  s^2 -200s -480000 = 0 . . . . . . . . . . rewrite in standard form

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The positive value of s that makes a factor zero is s = 800.

<u>Conclusion</u>

The speed of the faster plane was 800 km/h; of the slower plane, 600 km/h.

_____

<em>Check</em>

The travel time for the faster plane was 3600/800 = 4.5 hours. For the slower plane, 3600/600 = 6 hours, a difference of 1.5 hours.

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