For this case we have the following expression:

Rewriting the expression we have:
We apply distributive property to the terms of parentheses:

Answer:

Answer:

On this case n =6 and x =6 we got:

Step-by-step explanation:
The utility for the combination formula is in order to find the number of ways to order a set of elements
For this case we want to find the following expression:

And the general formula for combination is given by:

On this case n =6 and x =6 we got:

The equation <u>6 + 9a = 51</u> can help find out how many adults were in the group.