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Alex787 [66]
3 years ago
6

" class="latex-formula">
Basically (6x-3y)(6x-3y)
in standard form please with explanation
Mathematics
1 answer:
Snezhnost [94]3 years ago
5 0
<h3>36x^2 - 36xy + 9y^2 is the standard form</h3>

<em><u>Solution:</u></em>

<em><u>Given expression is:</u></em>

(6x-3y)^2

We have to write in standard form

Standard form means we have to write the terms by descending degree

Expand the given expression

(6x-3y)^2 = (6x-3y)(6x-3y)\\\\Simplify\\\\\rightarrow 36x^2 -18xy -18y +9y^2\\\\\rightarrow 36x^2 -36xy + 9y^2

Thus the expression is written in standard form

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\textsf{Let y = ax + b the line we want to find.}

\textsf{We know that the slope of y = ax + b is the inverse of the slope of } \mathsf{ y = \frac{1}{4}x - 2.}

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\textsf{Hence the line y = 4x - 22 is perpendicular to }\mathsf{y=\frac{1}{4}x - 2}\textsf{ and passes for the point (5, -2).}

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