Given that,
Sample size= 83
Mean number= 39.04
Standard deviation= 11.51
We know the critical t-value for 95% confidence interval which is equal to 1.989.
We also know the formula for confidence interval,
CI=( mean number - critical t-value*standard deviation/(sample size)^(1/2), mean number + critical t-value*standard deviation/(sample size)^(1/2))
So, we have
CI= (39.04 - 1.989*11.51/83^(1/2), 39.04 + 1.989*11.51/83^(1/2)
CI= (39.04 - 2.513,39.04 + 2.513)
CI= (36.527,41.553)
Therefore, 95% confidence interval for these data is (36.527,41.553), and this result interpret that the true value for this survey sample lie in the interval (36.527,41.553).
Answer:
This table is a guess-and-check, which means that you input whatever number you think might work in this situation in “city gallons”
Step-by-step explanation:
After you just input that same number to wherever the “6” was in the first row...
E.g., if you put “7” for the next “city gallons”, then you’d put “10 - 7 = 3” in “freeway gal” and so on with ever different number you put in for “city gallons”.
That last part in the way bottom goes the same way! Except you input ”c” instead of a number, which is how you find the actual correct answer.
Hope this helps :)
I hope this helps you
x= -3
f (-3)= -2.(-3)-3
f (-3)= 6-3
f (-3)=3
Answer: some parts of your question is missing below is the missing data
Determine if the given vector field F is conservative or not. F = −6e^y, (−6x + 3z + 9)e^y, 3e^y
answer:
F is conservative
F = -6xe^y + ( 33 + 9 ) e^y + C
Step-by-step explanation:
The Potential functions for F so that F = ∇f.
F = -6xe^y + ( 33 + 9 ) e^y + C
attached below is a detailed solution
Divide the number of ice-cream bars into the number of people. Example: say you have 20 ice cream bars and 10 people you divide 20/10 and get 2 ice cream bars per person. Hope this helped.
