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bagirrra123 [75]

3 years ago

7

Plz Help

1 answer:

netineya [11]3 years ago

3 0

Answer is 9r

Because 9x3 is 27
Also no clue about the brainliest thing

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andrey2020 [161]

First observe that if $a+b>0$ ,

$(a + b)^2 = a^2 + 2ab + b^2 \\\\ \implies a + b = \sqrt{a^2 + 2ab + b^2} = \sqrt{a^2 + ab + b(a + b)} \\\\ \implies a + b = \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b(a+b)}} \\\\ \implies a + b = \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b(a+b)}}} \\\\ \implies a + b = \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b \sqrt{\cdots}}}}$

Let $a=0$ and $b=x$ . It follows that

$a+b = x = \sqrt{x \sqrt{x \sqrt{x \sqrt{\cdots}}}}$

Now let $b=1$ , so $a^2+a=4x$ . Solving for $a$ ,

$a^2 + a - 4x = 0 \implies a = \dfrac{-1 + \sqrt{1+16x}}2$

which means

$a+b = \dfrac{1 + \sqrt{1+16x}}2 = \sqrt{4x + \sqrt{4x + \sqrt{4x + \sqrt{\cdots}}}}$

Now solve for $x$ .

$x = \dfrac{1 + \sqrt{1 + 16x}}2 \\\\ 2x = 1 + \sqrt{1 + 16x} \\\\ 2x - 1 = \sqrt{1 + 16x} \\\\ (2x-1)^2 = \left(\sqrt{1 + 16x}\right)^2$

(note that we assume $2x-1\ge0$ )

$4x^2 - 4x + 1 = 1 + 16x \\\\ 4x^2 - 20x = 0 \\\\ 4x (x - 5) = 0 \\\\ 4x = 0 \text{ or } x - 5 = 0 \\\\ \implies x = 0 \text{ or } \boxed{x = 5}$

(we omit $x=0$ since $2\cdot0-1=-1\ge0$ is not true)

3 0

2 years ago

Fcffffghvfdfffffgggggggg

Sauron [17]

Answer:

Yes

Step-by-step explanation:

?

3 0

3 years ago

Read 2 more answers

Simplify the following using PEMDAS:<br> 20 / (7-2)*3

Schach [20]

Answer:

if the * is equal to multiply, the answer is 12

Step-by-step explanation:

6 0

3 years ago

43. Find the image of the point (1,2) when reflected<br>by the line x=-1

dolphi86 [110]

Answer:

-3, 2

Step-by-step explanation:

4 0

3 years ago

What is the y intercept of the equation of the line that is perpendicular to the line y=3/5x+10 and passes through the point (15

Mama L [17]

It's 20/3. hope it will help you!

5 0

3 years ago