All categories

3 years ago

Which trigonometric function has the same value as sin 75°?

Mathematics

2 answers:

monitta3 years ago

6 0

Answer:

cos 15 degrees is your answer.

Answer choice (b)

Jobisdone [24]3 years ago

6 0

Answer: The correct answer is B cos 15 :)

You might be interested in

What is 1/5 ÷ 5<br> someone pls help me

Elena-2011 [213]

Answer: 1/25 or 0.04

Step-by-step explanation:

1/5 divided by 5 for the whole number you have to turn it to a fraction so you would do 5/1

THEN: it becomes 1/5 divided by 5/1 but you have to do the inverse so the inverse of division is multiplying and you will cross multiply so 5*5= 25 and 1*1=1 therefor the final answer is 1/25

5 0

2 years ago

Read 2 more answers

Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S.

sweet-ann [11.9K]

Answer:

2.794

Step-by-step explanation:

Recall that if G(x,y) is a parametrization of the surface S and F and G are smooth enough then

$\bf \displaystyle\iint_{S}FdS=\displaystyle\iint_{R}F(G(x,y))\cdot(\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y})dxdy$

F can be written as

F(x,y,z) = (xy, yz, zx)

and S has a straightforward parametrization as

$\bf G(x,y) = (x, y, 3-x^2-y^2)$

with 0≤ x≤1 and 0≤ y≤1

$\bf \displaystyle\frac{\partial G}{\partial x}= (1,0,-2x)\\\\\displaystyle\frac{\partial G}{\partial y}= (0,1,-2y)\\\\\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y}=(2x,2y,1)$

we also have

$\bf F(G(x,y))=F(x, y, 3-x^2-y^2)=(xy,y(3-x^2-y^2),x(3-x^2-y^2))=\\\\=(xy,3y-x^2y-y^3,3x-x^3-xy^2)$

and so

$\bf F(G(x,y))\cdot(\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y})=(xy,3y-x^2y-y^3,3x-x^3-xy^2)\cdot(2x,2y,1)=\\\\=2x^2y+6y^2-2x^2y^2-2y^4+3x-x^3-xy^2$

we just have then to compute a double integral of a polynomial on the unit square 0≤ x≤1 and 0≤ y≤1

$\bf \displaystyle\int_{0}^{1}\displaystyle\int_{0}^{1}(2x^2y+6y^2-2x^2y^2-2y^4+3x-x^3-xy^2)dxdy=\\\\=2\displaystyle\int_{0}^{1}x^2dx\displaystyle\int_{0}^{1}ydy+6\displaystyle\int_{0}^{1}dx\displaystyle\int_{0}^{1}y^2dy-2\displaystyle\int_{0}^{1}x^2dx\displaystyle\int_{0}^{1}y^2dy-2\displaystyle\int_{0}^{1}dx\displaystyle\int_{0}^{1}y^4dy+\\\\+3\displaystyle\int_{0}^{1}xdx\displaystyle\int_{0}^{1}dy-\displaystyle\int_{0}^{1}x^3dx\displaystyle\int_{0}^{1}dy-\displaystyle\int_{0}^{1}xdx\displaystyle\int_{0}^{1}y^2dy$

=1/3+2-2/9-2/5+3/2-1/4-1/6 = 2.794

5 0

3 years ago

Please help<br><br> y = -2/3

Arisa [49]

Answer: straight line across on the y axis on -2/3

Step-by-step explanation:

6 0

3 years ago

On friday taylor babysat for 4 hours and was paid $60. on saturday she babysat for 2 hours and was paid $30. what is the rate ta

Goshia [24]

Answer:

15 dollars per hour

Step-by-step explanation:

She is constantly charging 15 per hour.

3 0

3 years ago

Read 2 more answers

If an object is projected upward from ground level with an initial velocity of 128 ft per sec, then it's height in feet after t

antoniya [11.8K]

Answer: t= 4 seconds

Maximum height = 256 feet

Step-by-step explanation:

The height of the object projected upwards after t seconds is given by

s(t)=-16t^2+128t.

The expression is a quadratic equation. When this equation is plotted on a graph, height against time, it takes the shape of a parabola whose vertex represents the maximum height attained by the object.

To get the value of t at the maximum height,

t = -b/2a

From the equation,

a = -16

b = 128

t = -128/-2×-16

= -128 /- 32= 4

it will take 4 seconds to reach its maximum height

To find maximum height attained, put t= 4 in the equation

s(t)=-16t^2+128t

S = -16× 4^2 + 128×4

S = -256+512

S = 256 feet

3 0

3 years ago