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dlinn [17]
3 years ago
9

For the arthritic sequence 5,9,13,17,21,... how many terms would you need to get to 129

Mathematics
1 answer:
Vlad1618 [11]3 years ago
8 0

9514 1404 393

Answer:

  32

Step-by-step explanation:

The first term is 5 and the common difference is 9-5=4, so the n-th term is ...

  an = a1 +d(n -1)

  an = 5 +4(n -1) = 4n +1

Then the term number for the term 129 is ...

  129 = 4n +1 . . . . . put the given value in the formula

  128 = 4n  . . . . . . . subtract 1

  32 = n . . . . . . . . . .divide by 4

The 32nd term is 129.

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3. Antony and Cleopatra are 100 miles apart . To meet at a planned location , Antony travels at 12 mph and Cleopatra travels at
Vlad1618 [11]

Answer:

60 miles

Step-by-step explanation:

Distance apart = 100

Rate of travel. :

Anthony = 12 mph

Cleopafda = 8 mph

Using the relation :

Speed = distance / time

Distance = speed * time

If they leave at the same time, travel time Can be represented as x

Anthony's distance + Cleopafda distance = total distance

12x +. 8x = 100

20x = 100

x = 5

Hence, they both traveled for 5 hours before meeting.

Distance covered by Anthony :

Speed * time

12 mph * 5h = 60 miles

Anthony must travel. For 60 miles.

5 0
3 years ago
Gia bought a pound of cheese and used 1/4 of it. She split the rest into 5 equal portions for lunch during the week. Which expre
Reptile [31]
Gia already used 1/4. 3/4 divided by 5 = 3/20
7 0
3 years ago
I need this answered Fast if possible. A car is traveling on a small highway and is either going 55 miles per hour or 35 miles
Alex787 [66]

a. It spends about 2.045 hours going 55 miles per hour

b. It spends 1 hour going 35 miles per hour

c. The trip would take about 3.64 hours

Step-by-step explanation:

A car is traveling on a small highway and is either going 55 miles per hour or 35 miles  per hour, depending on the speed limits, until it reaches its destination 200 miles  away

  • x represents the amount of time in hours that the car is going 55 miles per  hour
  • y represents the amount of time in hours that the car is going 35 miles per hour
  • The equation  that describing the relationship is 55x + 35y = 200

We need to find:

a. How long does it  spend going 55 miles per hour, if the car spends 2.5 hours going 35 miles per hour on the trip

∵ 55x + 35y = 200

∵ The car spends 2.5 hours going 35 miles per hour on the trip

∵ y represents the amount of time that the car going 35 mi./h

∴ y = 2.5

- Substitute the value of y in the equation to find the value of x

∴ 55x + 35(2.5) = 200

∴ 55x + 87.5 = 200

- Subtract 87.5 from both sides

∴ 55x = 112.5

- Divide both sides by 55

∴ x = 2.045 hours

It spends about 2.045 hours going 55 miles per hour

b.how long does it  spend going 35 miles per hour, if the car spends 3 hours going 55 miles per hour on the trip

∵ 55x + 35y = 200

∵ The car spends 3 hours going 55 miles per hour on the trip

∵ x represents the amount of time that the car going 55 mi./h

∴ x = 3

- Substitute the value of y in the equation to find the value of x

∴ 55(3) + 35y = 200

∴ 165 + 35y = 200

- Subtract 165 from both sides

∴ 35y = 35

- Divide both sides by 35

∴ y = 1 hour

It spends 1 hour going 35 miles per hour

c. How long would the trip take, if the car spends no time going 35 miles per hour

∵ 55x + 35y = 200

∵ The car spends no time going 35 miles per hour

∴ y = 0

- Substitute the value of y in the equation to find the value of x

∴ 55x + 35(0) = 200

∴ 55x  = 200

- Divide both sides by 55

∴ x = 3.63 hours

The trip would take about 3.64 hours

Learn more:

You can learn more about the equations in brainly.com/question/4097107

#LearnwithBrainly

5 0
3 years ago
Help help help help help
Ugo [173]

Answer:

I'm pretty sure it's c but I'm not sure

8 0
3 years ago
find the length of each isosceles right triangle when the hypotenuse is of the given measure given 8cm
Wewaii [24]

It is given that the triangle is isosceles right triangle . And in an isosceles right triangle the legs are equal . Let each leg be of x units. Now we use pythagorean identity, which is

a^2 +b ^2=c^2

x^2 +x^2 = 8^2

2x^2 = 64

x^2 = 32

x = 4 \sqrt 2

So the length of each leg is 4 \sqrt 2 .

4 0
3 years ago
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