Complete question:
The manager of a supermarket would like to determine the amount of time that customers wait in a check-out line. He randomly selects 45 customers and records the amount of time from the moment they stand in the back of a line until the moment the cashier scans their first item. He calculates the mean and standard deviation of this sample to be barx = 4.2 minutes and s = 2.0 minutes. If appropriate, find a 90% confidence interval for the true mean time (in minutes) that customers at this supermarket wait in a check-out line
Answer:
(3.699, 4.701)
Step-by-step explanation:
Given:
Sample size, n = 45
Sample mean, x' = 4.2
Standard deviation
= 2.0
Required:
Find a 90% CI for true mean time
First find standard error using the formula:




Standard error = 0.298
Degrees of freedom, df = n - 1 = 45 - 1 = 44
To find t at 90% CI,df = 44:
Level of Significance α= 100% - 90% = 10% = 0.10

Find margin of error using the formula:
M.E = S.E * t
M.E = 0.298 * 1.6802
M.E = 0.500938 ≈ 0.5009
Margin of error = 0.5009
Thus, 90% CI = sample mean ± Margin of error
Lower limit = 4.2 - 0.5009 = 3.699
Upper limit = 4.2 + 0.5009 = 4.7009 ≈ 4.701
Confidence Interval = (3.699, 4.701)
Answer:
3 and 28
Step-by-step explanation:
note (
)(x ) = 

=
and
(
)(4) =
=
=
= 3
-------------------------------------------------------
(f + g)(x) = f(x) + g(x)
f(x) + g(x)
= x² + 2x - 3 + x² - 9 = 2x² + 2x - 12 and
(f + g)(4) = 2(4)² + 2(4) - 12 = 2(16) + 8 - 12 = 32 + 8 - 12 = 28
Answer:
27/sqrt9, 4^2 are the rational numbers
Step-by-step explanation:
All the other ones do not terminate, so this leaves these as the answers.
hope this helps!
Answer:
Your commission check for the 20% would be $160,000 and your 30% would be $240,000.
Step-by-step explanation:
To find each of these, multiply the total number of sales by the percentage of the commission.
$800,00*20% = $160,000
$800,000*30% = $240,000
Grace weighed 167 pounds before she started her exercise program.
Step-by-step explanation:
Given,
Weight lost by Grace = 45 pounds
Weight of Grace after exercise weeks = 122 pounds
Let,
x represents the weight of Grace before she started the exercise program.
Loss means subtraction, therefore,
We will subtract the lost weight from original weight.
Original weight - Weight lost = Weight after exercise weeks

Adding 45 on both sides

Grace weighed 167 pounds before she started her exercise program.
Keywords: equation, addition
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