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mr_godi [17]
3 years ago
11

Write an Equation using the following arithmetic sequence: 24, 18, 12

Mathematics
1 answer:
Jlenok [28]3 years ago
7 0

Answer:

24-18=6+6+12

hope this helps you!!

Step-by-step explanation:

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Artyom0805 [142]

Answer:

Starting with ΔABC, draw the dilation image of the triangle with a center at the origin and a scale factor of two. Notice that every coordinate of the original triangle has been multiplied by the scale factor (x2). Dilations involve multiplication! Dilation with scale factor 2, multiply by 2.

4 0
3 years ago
7/8 in decimal and percent form please and thank you
svetlana [45]

Answer:    Decimal: 0.875       Percent: 87.5%

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Reina and Sam are multiplying (84)5 (73)9.
Ann [662]
<span>This is a tricky question that Reina and Sam are multiplying (84)5 (73)9
and their work are 
</span><span>(84)5 (73)9 = 84 + 573 + 9 = 89712    Reina's
(84)5 (73)9 = 84⋅573⋅9 = 820727 Sam's
Actually they are doing or multiplying using exponents.

</span>

Reina’s work (8⁴)₅(7³)⁹=8⁴⁺⁵+ 7³⁺⁹= 8⁹ 7¹²<span>
This is incorrect  because she added exponents instead of multiplying exponents

Sams work (8</span>⁴<span>)</span>⁵<span> (7</span>³<span>)</span>⁹<span>=8</span>⁴ˣ⁵<span> 7</span>³ˣ⁹<span>= 8</span>²⁰<span> 7</span>²⁷<span>
<span>This is correct  because Sam multiplied exponents correctly</span></span>

<span><span>Exponents are multiplied not added.</span></span>

4 0
3 years ago
Write an algebraic expression for each word phrase the quotient of n and 6
CaHeK987 [17]

"The quotient of" tells you to use division. The order tells you which is the numerator and which is the denominator respectively.

n/6 is your answer. Or \frac{n}{6}

5 0
3 years ago
Gears produced by a grinding process are categorized either as conforming (suitable for their intended purpose), downgraded (uns
Svetach [21]

Answer:

A. P=0.4013

B. P=0.9884

C. P=0.3222

Step-by-step explanation:

We can model this with a binomial random variable.

The sample size is n=10.

The probability is p=0.05 for scrap and p=0.05+0.15=0.20 for degraded or scrap.

The probability of having k scrap gears in the sample is:

P(x=k) = \dbinom{n}{k} p^{k}(1-p)^{n-k}\\\\\\P(x=k) = \dbinom{10}{k} 0.05^{k} 0.95^{10-k}\\\\\\

The probability that one or more is scrap can be calculated as 100% less the probability that no one is scrap:

P(x\geq1)=1-P(x=0)\\\\\\P(x=0) = \dbinom{10}{0} p^{0}(1-p)^{10}=1*1*0.5987=0.5987\\\\\\P(x\geq1)=1-0.5987=0.4013

The probability that 8 or more are not scrap is equal to the probability of having 2 or less that are scrap:

P(x\leq2)=P(x=0)+P(x=1)+P(x=2)\\\\\\P(x=0) = \dbinom{10}{0} p^{0}(1-p)^{10}=1*1*0.5987=0.5987\\\\\\P(x=1) = \dbinom{10}{1} p^{1}(1-p)^{9}=10*0.05*0.6302=0.3151\\\\\\P(x=2) = \dbinom{10}{2} p^{2}(1-p)^{8}=45*0.0025*0.6634=0.0746\\\\\\P(x\leq2)=0.5987+0.3151+0.0746=0.9884

The probability that more than two are degraded or scrap (p=0.2) is calculated as:

P(x>2)=1-P(x\leq2)=1-(P(x=0)+P(x=1)+P(x=2))\\\\\\P(x=0) = \dbinom{10}{0} p^{0}(1-p)^{10}=1*1*0.1074=0.1074\\\\\\P(x=1) = \dbinom{10}{1} p^{1}(1-p)^{9}=10*0.2*0.1342=0.2684\\\\\\P(x=2) = \dbinom{10}{2} p^{2}(1-p)^{8}=45*0.04*0.1678=0.3020\\\\\\P(x>2)=1-(0.1074+0.2684+0.3020)=1-0.6778=0.3222

4 0
3 years ago
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