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iren2701 [21]
3 years ago
10

7 div 3/5 reciprocal

Mathematics
2 answers:
liraira [26]3 years ago
8 0

Answer:

Step-by-step explanation:

5/21

Natasha2012 [34]3 years ago
6 0

Answer:

7 : 3/5

7 * 5/3

35/3

11 2/3

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Mitzi has 79 coins she divides the coins equally among herself and her 3 brothers Mitzi will keep any coins left over how many c
Elanso [62]

Answer:

19

Step-by-step explanation:

79÷4=19R3

       ≈ 19

7 0
3 years ago
7cm<br>10cm<br>4cm<br>The area of the compound shape is 106cm.<br>work out the size of x.​
uranmaximum [27]

Answer: 9cm

Step-by-step explanation:

7x10=70cmx^{2}

4(x)=4x

1.) 70+4x=106 (subtract 70 on both sides)

2.)4x=36 (divide 4 on both sides)

3.)x=9

5 0
4 years ago
Read 2 more answers
Use partial products to multiply 2,104 x 8. 2,104 32 8 x 4 ones 0 8 x 0 tens N 1 hundreds 8 x 2 thousands - 16.000​
xeze [42]

9514 1404 393

Answer:

  16832

Step-by-step explanation:

As your problem statement says, ...

  2104 × 8 = 4×8 +00×8 +100×8 +2000×8

  = 32 +0 +800 +16000

  = 16,832

7 0
3 years ago
Solve the system of linear equations by elimination 2x+7y=1 2x-4y=12
pishuonlain [190]

\left\{\begin{array}{ccc}2x+7y=1\\2x-4y=12&\text{change the signs}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}2x+7y=1\\-2x+4y=-12\end{array}\right}\qquad\text{add both sides of equations}\\.\qquad\qquad11y=-11\qquad\text{divide both sides by 11}\\.\qquad\qquad \boxed{y=-1}\\\\\text{Put the value of y to the first equation:}\\\\2x+7(-1)=1\\2x-7=1\qquad\text{add 7 to both sides}\\2x=8\qquad\text{divide both sides by 2}\\\boxed{x=4}\\\\Answer:\ \boxed{x=4\ and\ y=-1\to(4,\ -1)}

3 0
4 years ago
a fruit delivers its fruit in two types of boxes: large and small. a delivery of 3 large boxes and 5 small boxes has a total wei
Masteriza [31]

Answer:

The weight of a small box  = 13.5 kg

The weight of 1 large box = 18.5 kg

Step-by-step explanation:

Let us assume the weight of a small box = m kg

And the weight of 1 large box  = n kg

Now, the weight of 5 small box = 5 x (weight of 1 small box) =  5 m

Also, the weight of 3 large box = 3 x (weight of 1 large box) =  3 n

Here,   3 large boxes +  5 small boxes =  of 123 kilograms

⇒ 5  m + 3 n = 123   .... (1)

Again, the weight of 2 small box = 2 x (weight of 1 small box) =  2 m

Also, the weight of 12 large box = 12 x (weight of 1 large box) =  12 n

Here,   12 large boxes +  2 small boxes =  249 kilograms

⇒ 2 m+ 12 n = 249   .... (2)

Now, solving both the given equations by ELIMINATION, we get:

5  m + 3 n = 123     x (2)

2 m+ 12 n = 249     x (-5)

we get the new set of equitation as:

10 m + 6 n = 246

- 10 m - 60 n =  -1245

Adding both equation, we get

-54 n = 999

or, n = 18.5

Now, 5  m + 3 n = 123

So, 5 m = 123  -3 (18.5)  = 123 - 55.5 =  67.5

⇒  m = 13.5

Hence,  the weight of a small box = m kg = 13.5 kg

And the weight of 1 large box = n kg  = 18.5 kg

8 0
3 years ago
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