4.5. because ⁼3=9, and 9 divided by 2 is 4.5
1. 32.66
2.3.25
3.4.103
4.0.42
5.6.109
6.6.1
7.184.02
8.905.26
Firstly, we'll fix the postions where the
women will be. We have
forms to do that. So, we'll obtain a row like:

The n+1 spaces represented by the underline positions will receive the men of the row. Then,

Since there is no women sitting together, we must write that
. It guarantees that there is at least one man between two consecutive women. We'll do some substitutions:

The equation (i) can be rewritten as:

We obtained a linear problem of non-negative integer solutions in (ii). The number of solutions to this type of problem are known: ![\dfrac{[(n)+(m-n+1)]!}{(n)!(m-n+1)!}=\dfrac{(m+1)!}{n!(m-n+1)!}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5B%28n%29%2B%28m-n%2B1%29%5D%21%7D%7B%28n%29%21%28m-n%2B1%29%21%7D%3D%5Cdfrac%7B%28m%2B1%29%21%7D%7Bn%21%28m-n%2B1%29%21%7D)
[I can write the proof if you want]
Now, we just have to calculate the number of forms to permute the men that are dispposed in the row: 
Multiplying all results:

Answer:
96
Step-by-step explanation:
i. Domain and Range
The given function is

The domain of this function is,



The range refers to the y-values for which x is defined. x is defined for all values of y.
The range is all real numbers. See graph
ii. x-and-y-intercept
For x- intercept intercept we put 
This implies that;

This will give us







The x-intercepts are 
For y-intercept, we put
to obtain;


The y-intercept is

iii. Horizontal asyptote
Since degree of the numerator and the denominator are the same, there is a horizontal asymptote
To find the horizontal asymptote.
We divide the leading coefficient of the numerator by the leading coefficient of the denominator.
The horizontal asymptote is 
iv. Vertical asymptote
To find the vertical asymptote, we equate the denominator to zero to get;

This implies that;

Split the middle term

Factor

Factor further


The vertical asymptotes are 