Here it is given that AB || CD
< EIA = <GJB
Now
∠EIA ≅ ∠IKC and ∠GJB is ≅ ∠ JLD (Corresponding angles)
∠EIA ≅ ∠GJB then ∠IKC ≅ ∠ JLD (Substitution Property of Congruency)
∠IKL + ∠IKC 180° and ∠DLH + ∠JLD =180° (Linear Pair Theorem)
So
m∠IKL + m∠IKC = 180° ....(1)
But ∠IKC ≅ ∠JLD
m∠IKC = m∠JLD (SUBTRACTION PROPERTY OF CONGRUENCY)
So we have
m∠IKL + m∠JLD = 180°
∠IKL and ∠JLD are supplementary angles.
But ∠DLH and ∠JLD are supplementary angles.
∠IKL ≅ ∠DLH (CONGRUENT SUPPLEMENTS THEOREM)
A line passing through the origin.
Answer:
the answer is 310
Step-by-step explanation:
|2x-3|=2x-1
need to consider two cases
(1) 2x-3<0 --> x<3/2
-(2x-3)=2x-1
x=1, and this is <3/2 so that's a valid solution
(2) 2x-3>=0 --> x>=3/2
2x-3=2x-1
-3 = -1 so there no solution for x>=3/2
The single solution is x=-1
