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Kobotan [32]
3 years ago
13

Not sure how to approach this one, any help would be appreciated!

Mathematics
1 answer:
iren2701 [21]3 years ago
8 0
The continuity of f' and its limiting behavior guarantees that f' is Riemann integrable, so you can write

\displaystyle\int_0^\infty f'(x)\,\mathrm dx=uv\bigg|_{x=0}^{x\to\infty}-\int_0^\infty v\,\mathrm du

where u=1\implies\mathrm du=0\,\mathrm dx and \mathrm dv=f'(x)\,\mathrm dx\implies v=f(x), so that

\displaystyle\int_0^\infty f'(x)\,\mathrm dx=f(x)\bigg|_{x=0}^{x\to\infty}=\lim_{x\to\infty}f(x)-f(0)=-f(0)
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Consider a Triangle ABC like the one below. Suppose that C = 98, A = 74, and b = 11 (figure is not drawn to scale.) solve the tr
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Answer:

A=73.8\°

B=8.2\°

c=76.3\ units

Step-by-step explanation:

step 1

Find the measure of side c

Applying the law of cosines

c^{2}= a^{2}+b^{2}-2(a)(b)cos(C)

substitute the given values

c^{2}= 74^{2}+11^{2}-2(74)(11)cos(98\°)

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step 2

Find the measure of angle A

Applying the law of sine

\frac{a}{sin(A)}=\frac{c}{sin(C)}

substitute the given values

\frac{74}{sin(A)}=\frac{76.3}{sin(98\°)}

sin(A)=(74)sin(98\°)/76.3

A=arcsin((74)sin(98\°)/76.3)

A=73.8\°

step 3

Find the measure of angle B

we know that

The sum of the internal angles of a triangle must be equal to 180 degrees

so

A+B+C=180\°

substitute the given values

73.8\°+B+98\°=180\°

171.8\°+B=180\°

B=180\°-171.8\°=8.2\°

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