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3 years ago

Why is it important to be able to represent functions as tables, graphs, algebraically, and verbally?

Mathematics

1 answer:

Sergio039 [100]3 years ago

3 0

Answer:

Step-by-step explanation:

A function can be represented verbally. For example, the circumference of a square is four times one of its sides.

A function can be represented algebraically. For example,

A function can be represented numerically.

A function can be represented graphically.

Key Terms

function: a relation in which each element of the domain is associated with exactly one element of the co-domain

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A marine sales dealer Önds that the average price of a previously owned boat is $6492. He decides to sell boats that will appeal

Anuta_ua [19.1K]

Answer:

The maximum price that the dealer will sell is $7471 and the minimum is $5513.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 6492, \sigma = 1025$

Middle 66%

50 - (66/2) = 17th percentile

50 + (66/2) = 83rd percentile

17th percentile

X when Z has a pvalue of 0.17. So X when Z = -0.955.

$Z = \frac{X - \mu}{\sigma}$

$-0.955 = \frac{X - 6492}{1025}$

$X - 6492 = -0.955*1025$

$X = 5513$

83rd percentile

X when Z has a pvalue of 0.83. So X when Z = 0.955.

$Z = \frac{X - \mu}{\sigma}$

$0.955 = \frac{X - 6492}{1025}$

$X - 6492 = 0.955*1025$

$X = 7471$

The maximum price that the dealer will sell is $7471 and the minimum is $5513.

4 0

3 years ago

Write a function that solves the matrix equation Ax = b using Gaussian Elimination (book section 6.2). Your function should acce

Luba_88 [7]

Answer:

See explaination

Step-by-step explanation:

public class GaussElim{

private static final double eps = 1e-10; % set epsilon value

public static doublic[] fun(double[][] A,double[] b){

int n=b.length; %calculate length of vector b.

for( int j=0;j<n;j++){

int max=j; %find and swap pivot row.

for (int i=j+1;i<n;i++){

if(Math.abs(A[i][j])>Math.abs(A[max][j])){

max=i;

}

double[] t1= A[j]; %swap

A[j]=A[max];

A[max]=t1;

double t= b[j]; %swap

b[j]=b[max];

b[max]=t;

if(Math.abs(A[j][j])<=eps){

throw new ArithmeticException("Matrix is singular."); % if matrix A is a singular matrix then throw error.

}

for(int i=j+1;i<n;i++){

double alpha= A[i][j]/A[j][j];

b[i]=b[i]-alpha*b[j];

for(int k=j;k<n;k++){

A[i][k]=A[i][k]-alpha*A[j][k];

}

double[] x=new double[n]; % back substitution starts here

for(int i=n-1;i>=0;i--){

double sum=0.0;

for(int j=i+1;j<n;j++){

sum=sum+A[i][j]*x[j];

}

x[i]=(b[i]-sum)/A[i][i];

}

return x;

}

public static void main(String[] args){

int n=3;

double[][] A={{1,2,1},{4,2,0},{-1,5,-3}};

double[] b={5,3,21};

double[] x=fun(A,b);

for(int i=0;i<n;i++){

StdOut.println(x[i]);

}

5 0

3 years ago

Street H is perpendicular to the line 2x –3y = –4 and goes (0, –6). Write this street’s equation in standard form.

storchak [24]

Answer:

I think its 68 + 1 = 69

Step-by-step explanation:

6 0

3 years ago

What is the domain and limit(s) of f(x)=1/x+3?

SVEN [57.7K]

Find the domain by finding where the function is defined. The range is the set of values that’s correspond with the domain

7 0

2 years ago

Use elimination to solve each system below.

aliina [53]

Answer:

System 1 : {3,0}; System 2 : {6,-2}

Step-by-step explanation:

2x + 3y = 6

-2x - y = -6

2y = 0

y = 0

-2x = -6

x = 3

system 2

2x + 3y = 6

2x + 2y = 8

y = -2

2x -4 = 8

2x = 12

x = 6

6 0

2 years ago