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Sladkaya [172]
2 years ago
8

A share of ABC stock was worth $70 in 2011 and only

Mathematics
1 answer:
Bezzdna [24]2 years ago
6 0

Answer:

5v + 32y = 350

Step-by-step explanation:

Let, the year counting starts in 2011 and represented by y.

So, the share of ABC stock value was $70 at y = 0. And in the year 2016 i.e. y = (2016 - 2011) = 5, the share worth $38.

If there is a linear relationship between the number of years since 2011 i.e. y and the value of the share of ABC stock i.e. v, then we can write the equation of this situation as

\frac{v - 70}{70 - 38} = \frac{y - 0}{0 - 5}

⇒ 5v - 350 = - 32y

⇒ 5v + 32y = 350 (Answer)

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Consider the function g(x) = (x-e)^3e^-(x-e). Find all critical points and points of inflection (x, g(x)) of the function g.
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Answer:

The answer is "cirtical\  points \ (x,g(x))\equiv  (e,0),(e+3,\frac{27}{e^3})"

Step-by-step explanation:

Given:

g(x) = (x-e)^3e^{-(x-e)}

Find critical points:

g(x) = (x-e)^3e^{(e-x)}

differentiate the value with respect of x:

\to g'(x)= (x-e)^3 \frac{d}{dx}e^{e-r} +e^{e-r}  \frac{d}{dx}(x-e)^3=(x-e)^2 e^{(e-x)} [-x+e+3]

critical points g'(x)=0

\to (x-e)^2 e^{(e-x)} [e+3-x]=0\\\\\to e^{(e-x)}\neq 0 \\\\\to (x-e)^2=0\\\\ \to [e+3-x]=0\\\\\to x=e\\\\\to x=e+3\\\\\to x= e,e+3

So,

The critical points of (x,g(x))\equiv  (e,0),(e+3,\frac{27}{e^3})

7 0
3 years ago
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C

Step-by-step explanation:

The formula for finding the distance between 2 points (x1, y1) and (x2, y2) is

d = √[(x2 - x1)² + (y2 - y1)²]

Here (x2, y2) = (2, 3)  and (x1, y1) = (4, -3)

Plugging them gives us

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8 0
3 years ago
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Answer:

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