All categories

4 years ago

Plz help me with this quesiton

Mathematics

2 answers:

Digiron [165]4 years ago

5 0

C. 375/2 times 3 us 562.5, which is 562 1/2.

oksano4ka [1.4K]4 years ago

3 0

It is B. There are three 1/2's in 1 1/2. 1 1/2/3= 1/2.
Because you did this to 1/2, you must do it to 375. 375/3 = 125.
1/2* 2= 1. *** 1 pound is what you're aiming for.
125 * 2 = 250.
So B would be the answer

You might be interested in

Simplify the equation (2+√3 + 1/2+√3)²

Andreyy89

73/4 + 10√3 I think I’m not sure.

7 0

3 years ago

Read 2 more answers

What is 1/10 of 30,000?

Zanzabum

To solve, multiply

1/10 x 30,000

Note that multiplying 30,000 with 1/10 is the same as dividing 10 from 30,000

30000/10 = 3000

3,000 is your answer

hope this helps

4 0

3 years ago

6.2megagrams/hectoliter to kilograms/deciliter

lesya [120]

Answer:

6.2 kilograms/ deciliters

Step-by-step explanation:

megagrams to kilograms

1 megagram = 1000 kilograms

hectoliter to deciliter

1 hectoliter = 1000 deciliter

Using conversion factors

6.2megagrams 1000 kilgrams 1 hectoliter

---------------------- * ----------------------- * -------------------------

hectoliter 1 megagram 1000 deciliters

Canceling like terms

6.2 kilograms/ deciliters

6 0

3 years ago

Read 2 more answers

Mr. Johnson has a garden in the shape of a kite with a length of 5 feet and a width of 4 feet. A bag of topsoil covers 10 square

ad-work [718]

Answer:

5, 10, 1

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

At the start of the year, 15 chameleons were introduced into a zoo. The population of chameleons is expected to grow at a rate o

bearhunter [10]

Answer:

option-B

Step-by-step explanation:

We are given

At the start of the year, 15 chameleons were introduced into a zoo

so, $P_0=15$

The population of chameleons is expected to grow at a rate of 41.42% every year

so, r=0.4142

and x represents the number of years since the chameleons were introduced into the zoo

now, we can set equation to find total population

and we get

$P(x)=P_0(1+r)^x$

now, we can plug values

$P(x)=15(1+0.4142)^x$

$P(x)=15(1.4142)^x$

Average rate of change between 2 years and 4 years:

we can use formula

$A_1=\frac{P(4)-P(2)}{4-2}$

now, we can plug values

$A_1=\frac{15(1.4142)^{4}-15(1.4142)^{2}}{4-2}$

$A_1=14.99914$

Average rate of change between 4 years and 6 years:

we can use formula

$A_2=\frac{P(6)-P(4)}{6-4}$

now, we can plug values

$A_2=\frac{15(1.4142)^{6}-15(1.4142)^{4}}{6-4}$

$A_2=29.99770$

Average rate of change between 6 years and 8 years:

we can use formula

$A_3=\frac{P(8)-P(6)}{8-6}$

now, we can plug values

$A_3=\frac{15(1.4142)^{8}-15(1.4142)^{6}}{8-6}$

$A_3=59.99425$

now, we will check each options

option-A:

we can see that

$A_3-A_2=30$

So, this is FALSE

option-B:

$A_1=\frac{1}{2}A_2$

So, this is TRUE

option-C:

This is FALSE

option-D:

we got

$A_1=\frac{1}{2}A_2$

so, this is FALSE

5 0

3 years ago