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3 years ago

What is 1/10 of 30,000?

Mathematics

1 answer:

Zanzabum3 years ago

4 0

To solve, multiply

1/10 x 30,000

Note that multiplying 30,000 with 1/10 is the same as dividing 10 from 30,000

30000/10 = 3000

3,000 is your answer

hope this helps

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The roof of the building shown below has a span of 48 feet. The rafters upon which the roof is laid are 30 feet long, including

anyanavicka [17]

Solution :

Given :

Span of the roof = 48 feet

Length of the rafter = 30 feet (including the 4 feet overhung)

So, for the 30 feet long rafter, 26 feet will be rafter length from the high point of the roof to the edge of the roof and 4 feet will be the roof overhung.

Therefore, the horizontal span per rafter is

$=\frac{48}{2}$

= 24 feet

a). So the rise of the roof is $= \sqrt{(26)^2-(24)^2}$

= 10 feet

b). Pinch of the roof is $=\frac{\text{rise}}{\text{run}}$

$=\frac{10}{24}$

$=\frac{5}{12}$

c). The percent of the roof used as overhung is

$=\frac{4+4}{60}\times 100$

$=\frac{80}{6}$

= 13.33 %

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2 years ago

Match with correct description

fgiga [73]

First one: If the leading coeff. is negative, the graph begins in Quadrant III and ends in Quadrant IV. It's an even function. The fourth graph represents it.

If the leading coeff. is positive, but everything else remains the same, the graph opens upward, beginning in Q II and ending in Q I.

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3 years ago

Simplify the following expression.<br> <br> 15p+15p+25p =

IrinaK [193]

15p+15p+25p=30p+25p=55p

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3 years ago

For a certain model of car the distance d required to stop the vehicle if it is traveling at v mi/h is given by the formula d =

enyata [817]

Given that <span>For a certain model of car the distance $d$ required to stop the vehicle if it is traveling at $v$ mi/h is given by the formula $d=v+\frac{v^2}{20}, where [tex]d$ is measured in feet.

If Kerry wants her stopping distance not to exceed 75 ft, then the range of speeds (in mi/h) can she travel is obtained as follows:

$v+ \frac{v^2}{20} \leq75 \\ \\ 20v+v^2\leq1,500 \\ \\ v^2+20v+100\leq1,500+100 \\ \\ (v+10)^2\leq1,600 \\ \\ |v+10|\leq\sqrt{1,600} \\ \\ -40\leq v+10\leq40 \\ \\ -40-10\leqv\leq v\leq40-10 \\ \\ -50\leq v\leq30$

Therefore, the range of speed she can travel is $v\leq30\ mi/hr$
</span>

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3 years ago

6. MONEY Len bought a $24.99 pair of pants

tatuchka [14]

Answer:

$2.06 tax

Step-by-step explanation:

$24.99 pants

$27.05 total cost with tax

24.99 + tax = 27.05

tax = 27.05 - 24.99

27.05 - 24.99 = 2.06

7 0

3 years ago