For each <em>x</em> in the interval 0 ≤ <em>x</em> ≤ 5, the shell at that point has
• radius = 5 - <em>x</em>, which is the distance from <em>x</em> to <em>x</em> = 5
• height = <em>x</em> ² + 2
• thickness = d<em>x</em>
and hence contributes a volume of 2<em>π</em> (5 - <em>x</em>) (<em>x</em> ² + 2) d<em>x</em>.
Taking infinitely many of these shells and summing their volumes (i.e. integrating) gives the volume of the region:
Answer:
201
Step-by-step explanation:
I'm smart ok trust me ON this one if I'M wrong at least I tried
You first subtract 1/5 from both sides
3/4-1/5 = 11/20
3/2x=11/20
now you multiply 2/3 on both sides since you have to get x
11/20 * 2/3
x = 11/30