All categories

3 years ago

Plz help with this question

Mathematics

1 answer:

e-lub [12.9K]3 years ago

4 0

since both equations are equal to y...

y = 2x + 10

y = -4x - 2

2x + 10 = y = -4x - 2

2x + 10 = -4x - 2

2x + (4x) = -2 + (-10)

6x = -12

x = -2

______________________________

plug in x = -2 into one of those equations: I will use y = 2x + 10

y = 2(-2) + 10

y = -4 + 10

y = 6

______________________________

okay, so I rechecked my answers several times, and I still got (-2,6)

That MC question has an error since none of the answer choices fit.

Inform your teacher about this.

(I'd say choose that (-3,4) since it works only for one equation y = 2x +10 .... maybe your teacher was supposed to use the other equation instead of y = -4x - 2)

You might be interested in

In an upcoming race, the top 3 finishers will be recognized with the same award. There are 12 people entered in the race.

slavikrds [6]

Answer:

220

Step-by-step explanation:

Given,

The total number of people = 12,

Out of which, top 3 finishers will be recognized with the same award,

So, the total possible way = total combination of 3 people out of 12 people

$=^{12}C_3$

$=\frac{12!}{3!(12-3)!}$

$=\frac{12\times 11\times 10\times 9!}{3\times 2\times 9!}$

$=\frac{1320}{6}$

$=220$

Hence, there are 220 ways the top 3 racers can be grouped from the 12 people.

6 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Crm%20%5Cint_%7B0%7D%5E%20%5Cinfty%20%20%5Cfrac%7B%20%5Csqrt%5B%20%20%5Cscriptsize%5Cphi%

Rasek [7]

With ϕ ≈ 1.61803 the golden ratio, we have 1/ϕ = ϕ - 1, so that

$I = \displaystyle \int_0^\infty \frac{\sqrt[\phi]{x} \tan^{-1}(x)}{(1+x^\phi)^2} \, dx = \int_0^\infty \frac{x^{\phi-1} \tan^{-1}(x)}{x (1+x^\phi)^2} \, dx$

Replace $x \to x^{\frac1\phi} = x^{\phi-1}$ :

$I = \displaystyle \frac1\phi \int_0^\infty \frac{\tan^{-1}(x^{\phi-1})}{(1+x)^2} \, dx$

Split the integral at x = 1. For the integral over [1, ∞), substitute $x \to \frac1x$ :

$\displaystyle \int_1^\infty \frac{\tan^{-1}(x^{\phi-1})}{(1+x)^2} \, dx = \int_0^1 \frac{\tan^{-1}(x^{1-\phi})}{\left(1+\frac1x\right)^2} \frac{dx}{x^2} = \int_0^1 \frac{\pi2 - \tan^{-1}(x^{\phi-1})}{(1+x)^2} \, dx$

The integrals involving tan⁻¹ disappear, and we're left with

$I = \displaystyle \frac\pi{2\phi} \int_0^1 \frac{dx}{(1+x)^2} = \boxed{\frac\pi{4\phi}}$

8 0

3 years ago

A card is drawn from a standard 52-card deck. what is the probability that the card is a club, or that the card is a red-suited,

BigorU [14]

The answer to your question is 2/26

5 0

3 years ago

Test scores in a Test were normally distributed with a mean of 75 and a standard deviation of 10. Carl scored 90 in the Test . W

mylen [45]

Answer:

Z-score = 1.5

Step-by-step explanation:

Z-score = (x-mean)/standard deviation

= (90-75)/10

= 1.5

6 0

3 years ago

How do I solve this step by step?

Zinaida [17]

Answer:

Step-by-step explanation:

plug in 3 where the xs are

2(3)(6(3)-5(3))+(3)^2(5(3)-4(3)=45

2(3)=6

6(3)=18

-5(3)=15

(3)^2=9

5(3)=15

-4(3)=-12

8 0

3 years ago