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skelet666 [1.2K]
3 years ago
11

Germaine walks at the rate of 10 feet every five seconds while Nolan walks at the rate of 15 feet every five seconds. If Germain

e has a head start of 25 feet, after how many seconds will they be at the same spot?
Mathematics
2 answers:
ankoles [38]3 years ago
8 0
They will get to 90 feet at <u>half a minute</u> or <u>30 seconds</u>.
artcher [175]3 years ago
3 0
For GERmain he needs 10 sec to walk the same as nolan


for noal he has the head start not germain and then every 10 sec and 3.9 sec noal walk he will be at the same time as germain
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What is the arc measure, in degrees, of major arc \stackrel{\large{\frown}}{ADC} ADC ⌢ A, D, C, start superscript, \frown, end s
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Answer:

\stackrel{\large{\frown}}{ADC}    = 186^{\circ}

Step-by-step explanation:

Given

See attachment

Required

Determine the measure of \stackrel{\large{\frown}}{ADC}

The\ sum\ of\ angles\ in\ a\ circle\ is 360^{\circ}.

So, we have:

\stackrel{\large{\frown}}{ADC} + \stackrel{\large{\frown}}{APB}  + \stackrel{\large{\frown}}{BPC}  = 360^{\circ}

Where:

\stackrel{\large{\frown}}{APB}  = 70^{\circ}

\stackrel{\large{\frown}}{BPC}  = 104^{\circ}

Substitute these values in the above equation.

\stackrel{\large{\frown}}{ADC} + 70^{\circ}   +104^{\circ}   = 360^{\circ}

\stackrel{\large{\frown}}{ADC} + 174^{\circ}   = 360^{\circ}

Collect Like Terms:

\stackrel{\large{\frown}}{ADC}    = 360^{\circ} - 174^{\circ}

\stackrel{\large{\frown}}{ADC}    = 186^{\circ}

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