2 years ago

Solve for x! show your work please :)

Mathematics

2 answers:

Luda [366]2 years ago

7 0

Answer:

x= 12

Step-by-step explanation:

16=24

2x-6= 18

2x= 18+6= 24

2x= 24

x= 24/2= 12

hope it helps!

Law Incorporation [45]2 years ago

6 0

Answer:

x=12

Step-by-step explanation:

Line AC and line PR are congruent.

2x-6=18

2x=24

x=12

You might be interested in

The students lockers at a college are to be numbered consecutively form 1 to 800 using plastic digits. Each digit cost 10c. What

KIM [24]

Answer would be eight because you divide eight hundred by ten cents to get eight.

6 0

3 years ago

Using a rule why is = to 3 x + 4 find the value of y when x is 2

Alex73 [517]

X=2 so 2+4=6 so y=6. I just gone ovee this unit aswell.

4 0

3 years ago

How can i find the área of a triangle? please help.

Anni [7]

This is the area of a triangle

7 0

2 years ago

Read 2 more answers

2х + y = 20<br> 6x — 5y = 12<br> How do i solve this? This is Systems of equations: Substitution

RideAnS [48]

12819=
Yx ..................................

6 0

3 years ago

There are eight students in a class. Only one of them has passed Exam P/1 and only one of them has passed Exam FM/2. No student

Svetach [21]

Answer: There is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.

Step-by-step explanation:

Total number of students = 8

Number of student who has passed Exam P/1 = 1

Number of student who has passed Exam FM/2 = 1

No student has passed more than one exam.

According to question, exactly three students from a randomly chose group of four students have not passed Exam P/1 or Exam FM/2.

So, Probability will be

$\frac{^6C_3\times ^2C_1}{^8C_4}\\\\=\frac{20\times 2}{70}\\\\=\frac{4}{7}\\\\=0.57$

Hence, there is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.

4 0

3 years ago