When using elimination, the objective is to elimate one variable. In this case, we see that "y" can easily be eliminated by adding the two equations together since you will get 3y + (-3y) which will eliminate y because the value would become 0, letting us solve for x.

$\left \{ {{8x+3y=28} \atop {7x-3y=2}} \right. +\\$

Then we get

$15x =30$ , because the y's will eliminated, and 8x+7x is 15x, and 28+2 is 30.

Then divide by 15 on both sides and you get x=2

If x=2, then we can substitute that value into any of the previous given equations and find the value of y.

8×2 +3y = 28

16+3y=28

3y=12

y=4

So the answer to your system of equations would be x=2, and y=4

You can substitute the answers we found to see that they satisfy the equation.

Hope this helped.

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3 years ago