The phosphorylation of fructose 6-phosphate to fructose-1,6-bisphosphate is the committed step in glycolysis because<u> fructose 1,6-bisphosphate can undergo no other reactions than those of glycolysis.</u>
<h3>
What is phosphorylation?</h3>
- The crucial process of glycolysis involves the breakdown of glucose into two molecules of pyruvate. It involves a number of steps and many enzymes.
- It takes place over the course of ten phases, demonstrating how important and crucial phosphorylation is to the production of the final goods. Step 1 of the preliminary step (first half of glycolysis) and step 6 of the payout phase reactions are started by phosphorylation (second phase of glycolysis).
- Because fructose-6-phosphate cannot cross the cell membrane, it is forced to remain inside the cell. Step 3 involves phosphorylation, when fructose-6-phosphate is changed into fructose-1,6-bisphosphate.
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Answer:
(x - 1)(x - 2)(x + 3)
Explanation:
f(x)=x3-7x+6 Since (a + b + c + d = 0), then f(1) = 0 --> one factor if (x - 1).
After division -->
f(x)=(x-1)(x2f2+x-6). The trinomial in parentheses can be factored.
Find 2 numbers knowing sum (1) and product (-6). They are -2 and 3.
Therefor, f(x)=(x-1)(x-2)(x+3)
Answer:
Phenotypes
Explanation:
'Phenotype' is just a fancy way of saying 'what an organism looks like'. Those words describe an organism's physical appearance and not its genetic makeup--that's its genotype.
You can remember it this way:
Phenotype
Physical characteristics/appearance
----
Genotype
Genetic makeup
Answer:
A. Glucose:
As lactose is absent will follow the glucose metabolism, so the lac repressor will hold tightly with the operator which leads to the prevention of transcription as RNA polymerase can not bind to promoter so no lactose metabolism.
B. lactose:
In the case or wild mutant lactose metabolism will occur as lactose is present, allolactose binds to the lac repressor thus the operator and promoter are free so transcription starts. The same result will be in all test except in the case of a mutant repressor.
C. glucose and lactose:
In this case, diauxic growth will occur. This growth takes place when two sugars are present in the media. The preferred sugar will be consumed first That is glucose. Then a lag phase will come which will be followed by the second sugar metabolism that is lactose. the given two cases :
Lactose will be metabolized first, as operator site mutation prevents repressor protein binding and thus will lead to the constitutive synthesis of lac operon in test B.
The same thing will happen, as in this case also, constitutive synthesis of lac operon will happen in test C.
Cultures grown in the presence of both glucose and lactose are metabolizing lactose. In the test (b) and (c) will be responsible due to constitutive synthesis of lac operon will happen.
Answer: Sustainable
Explanation:
Once a product can serve the present moment and remain useful for an indefinite period without polluting the environment, or getting reduced in value, it can be said to be SUSTAINABLE.
